Question

6. (x + 2)(3x - 1) - (x + 4)(x - 7) i’m confused

Answer 1

Answer:

$\large\boxed{(x+2)(3x-1)-(x+4)(x-7)=2x^2+8x+26}$

Step-by-step explanation:

$(x+2)(3x-1)-(x+4)(x-7)\\\\\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(x+2)(3x-1)=(x)(3x)+(x)(-1)+(2)(3x)+(2)(-1)\\\\=3x^2-x+6x-2=3x^2+(-x+6x)-2=3x^2+5x-2\\\\(x+4)(x-7)=(x)(x)+(x)(-7)+(4)(x)+(4)(-7)\\\\=x^2-7x+4x-28=x^2+(-7x+4x)-28=x^2-3x-28\\\\(x+2)(3x-1)-(x+4)(x-7)=(3x^2+5x-2)-(x^2-3x-28)\\\\=3x^2+5x-2-x^2-(-3x)-(-28)=3x^2+5x-2-x^2+3x+28\\\\=(3x^2-x^2)+(5x+3x)+(-2+28)\\\\=2x^2+8x+26$

Answer 2

Answer:

2x^2 +8x +26

Step-by-step explanation:

I think you're supposed to simplify this:

So what you do is: you must have learmt about FOIL

which means First, Outside, Inside, Last.

So, this is how to do it using FOIL:

(3x^2 -x+6x-2) - ( x^2-7x+4x-28)

Now simplify, combine like terms wherever you can,

(3x^2 +5x -2) - ( x^2 -3x -28)

Note: multiply the subtraction sign otherwise you will end up making a mistake,

3x^2 +5x -2 - x^2 +3x+28

3x^2 -x^2 +5x+3x-2+28

2x^2 +8x +26 Answer

Hope this helps!

Please mark brainliest if you think I helped! Would really appreciate!

Note: Some of these steps can be eliminated, i showed everything for the purpose of making things clear for you!