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Pavel [41]
3 years ago
13

2^x+3^2y=11 2^x+1-3^y=1

Mathematics
1 answer:
Marina86 [1]3 years ago
6 0

Answer:

x = 1, y = 1

Step-by-step explanation:

Let A = 2^x

Let B = 3^y

A + B² = 11

A = 11 - B²

2A - B = 1

22 - 2B² - B = 1

2B² + B - 21 = 0

2B² + 7B - 6B - 21 = 0

B(2B + 7) - 3(2B + 7) = 0

(2B + 7)(B - 3) = 0

B = -7/2, B = 3

A = 11 - 3²

A = 2

2 = 2^x

x = 1

3^y = 3

y = 1

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8 0
4 years ago
-2x -3y = 8<br> -2x + 4y = 22
11111nata11111 [884]
-2x + 4y = 22
-2x - 3y = 8

Subtract 2nd from 1st equation, 
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y = 14/7 = 2

Substitute it in 1st equation, 
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x = -14/2
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In short, Your Answer would be (-7, 2)

Hope this helps!
6 0
3 years ago
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vovangra [49]
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3 0
4 years ago
Write the equation for the inverse of the function.
Rashid [163]

Answer:

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Step-by-step explanation:

explanation is in the attachment above

8 0
3 years ago
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