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dedylja [7]
3 years ago
5

Kayla walked 4 kilometers due east before turning left and walking 2.5 kilometers due north. She turned again and returned to he

r starting point by walking a straight path. What was the angle of the last turn? Round to the nearest degree.
Mathematics
1 answer:
tatiyna3 years ago
8 0
<span>Kayla walks a path with a triangle shape with three corners, starting point A, point where turns north, B, and point where head towards start, C. The question is calculate the angle in the point C, knowing that A-B distance is 4 km and B-C is 2.5 To do this calculation we are going to use the trigonometry function tangent: tangent C = opposite/adjacent = 4/2.5 = 1.6 Then C angles is: C = arctan (1.6) = 57.99Âş So the solution is round to 58Âş</span>
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PLEASE HELP ITS EXTRA CREDIT AND I COULD REALLY USE IT !! BEING TIMED! for each of the following statements, determine if the st
bogdanovich [222]

A. True. We see this by taking the highest order term in each factor:

f(x) = -3x(x-5)^3(x+2)^2 = -3x (x^3 + \cdots) (x^2 + \cdots) = -3x^{\boxed{6}} + \cdots

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8 0
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Please help with question 4A,B please<br> Thank you
mrs_skeptik [129]
<h3>Given</h3>
  • C(t) = 40 cm + t·(2/5 cm/s) . . . circumference of a circle vs time
<h3>Find</h3>
  • dr/dt for radius r
  • r at t=4 seconds
<h3>Solution</h3>

The circumference and radius of a circle are related by

... C = 2πr

so the radius in terms of circumference is

... r = C/(2π)

... r(t) = (40 +0.4t)/(2π) = (1/π)(20 cm + 0.2t cm/s)

Then dr/dt is

... dr/dt = 0.2/π cm/s

And the radius at t=4 s is

... r(4) = (1/π)(20 + 0.2·4) cm

... r(4) = 20.8/π cm

4 0
3 years ago
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