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V125BC [204]
3 years ago
15

What is the net force on the image(NEED ASAP)

Mathematics
2 answers:
ollegr [7]3 years ago
8 0

Answer:

1200 N right

Step-by-step explanation:

Subtract 150 from 1350. Since there is more force towards the right, the net force is 1200 N right

Karolina [17]3 years ago
8 0

Answer:

1200N right

Step-by-step explanation:

To get the net force, since both forces are going towards opposite direction, we subtract the smaller force from the large one .

So ,

1350N - 150N

1200N

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sum of two numbers is 39. the greater number is 7 more than the smaller number. ( set up an equation )
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Citrus2011 [14]

Answer:

a.

<u>Increasing:</u>

x < 0

x > 2

<u>Decreasing:</u>

0 < x < 2

b.

-1 < x < 2

x > 2

c.

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Step-by-step explanation:

a.

Function is increasing when it is going up as we go rightward

Function is decreasing when it is going down as we go rightward

We can see that as we move up (from negative infinity) until x = 0, the function is increasing. Also, as we go right from x = 2 towards positive infinity, the function is going up (increasing).

So,

<u>Increasing:</u>

x < 0

x > 2

The function is going down, or decreasing, at the in-between points of increasing, that is from 0 to 2, so that would be:

<u>Decreasing:</u>

0 < x < 2

b.

When we want where the function is greater than 0, we basically want the intervals at which the function is ABOVE the x-axis [ f(x) > 0 ].

Looking at the graph, it is

from -1 to 2 (x axis)

and 2 to positive infinity

We can write:

-1 < x < 2

x > 2

c.

Now we want when the function is less than 0, that is basically saying when the function is BELOW the x-axis.

This will be the other intervals than the ones we mentioned above in part (b).

Looking at the graph, we see that the graph is below the x-axis when it is less than -1, so we can write:

x < -1

4 0
4 years ago
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