how is it possible for the expected value of a game to be losing 65 cents of the only outcomes are win $2 or lose $1

1 answer:

4 0

Let x be the probability of winning and let y be the probability of losing. Then we can write the following equation:
2x - y = -0.65 ..............(1)
the sum of the probabilities of winning and losing must equal 1.
x + y = 1............(2)
Rearranging (2), gives:
y = 1 - x ............(3)
Plugging the expression for y from (3) into (1), we get:
2x - 1 + x = -0.65
which simplifies to:
3x = 0.35
Therefore x = 0.117 and y = 0.883.
The expected value of the game will be a loss of 65 cents if the probability of winning is 0.117 and the probability of losing is 0.883.

You might be interested in

Find the point at which the line joining the two points (-3,-5) and (7,5) cuts they y axis

8090 [49]

Answer:

(0,-2)

Step-by-step explanation:

First we find the equation of the line passes through $(-3,-5)$ and $(7,5)$ .

The slope of the line is

$m=\frac{5-(-5)}{7-(-3)}\\=\frac{10}{10}\\=1$

So by the point slope formula the equation of the line is

$y-5=1(x-7)\\y=x-7+5\\y=x-2$

When $x=0$ we have $y=0-2=-2$ .

Therefore the line joining the two points cuts the y-axis at (0,-2).

4 0

2 years ago

True or false the expression 24 - 2x + 3y has three terms

Stells [14]

I believe the answer is false

3 0

3 years ago

Languages Spoken in Australia

RideAnS [48]

Answer Should be= B
Hope this helps.

4 0

3 years ago

Read 2 more answers

P(x)=x^3+2x^2-4x-8 how do you factor this polynomial function

Wewaii [24]

<h2>Steps:</h2>

So for this, I will be factoring by grouping. Firstly, factor x³ + 2x² and -4x - 8 separately. Make sure that they have the same quantity inside of the parentheses:

$p(x)=x^2(x+2)-4(x+2)$

Now we can rewrite it as:

$p(x)=(x^2-4)(x+2)$

However, we aren't finished factoring yet. The first factor, x² - 4, can be factored further using the difference of squares. The difference of squares goes by the formula here: $x^2-y^2=(x+y)(x-y)$ . In this case: