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Doss [256]
2 years ago
13

Please help with 7 :))

Mathematics
1 answer:
Maru [420]2 years ago
3 0
What Is Your. Answer
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Congruence transformation pls help im despo
Tomtit [17]

Answer:

X,2,3

Step-by-step explanation:

LEARN THIS PLZ

7 0
3 years ago
Read 2 more answers
Find the vertical asymptote. y = x - 1 / x + 4
Hatshy [7]

Answer:

x = - 4

Step-by-step explanation:

Given

y = \frac{x-1}{x+4}

The denominator of y cannot be zero as this would make y undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 4 = 0 ⇒ x = - 4

Thus the vertical asymptote is x = - 4

6 0
3 years ago
Can I please get Help With this Question?
kow [346]

Choice B) Commutative Property is the answer

The commutative property of addition says that we can add two numbers in any order. For example: 2+3 = 5 and 3+2 = 5.

In general, the rule can be written as x+y = y+x. The x and y are simply placeholders for numbers. You can think of them as empty boxes to write a number inside. In this case, we have 7.2 for one of the boxes and -5.5 as the other value in the other box.

6 0
3 years ago
Algebra help please !
umka2103 [35]

Answer:

g(f(0)) = 2

Step-by-step explanation:

To find g(f(0)), you must first find f(0).

f(x) = 3x + 1

f(0) = 3(0) + 1 = 0 + 1 = 1

Now you input 1 into function g(x).

g(x) = (4x + 2)/3

g(1) = [4(1) + 2]/3

g(1) = [4 + 2]/3

g(1) = 6/3

g(1) = 2

g(f(0)) = 2

6 0
2 years ago
Read 2 more answers
Please help!
Gemiola [76]

The earning of the salesperson is an illustration of a linear function.

The possible functions in the two scenarios are: \mathbf{I(s) = 0.1s + 2500} and \mathbf{I(s) = 0.05s + 2000}\\

The function is given as:

\mathbf{I(s) = 0.1s + 2000}

When the base salary is increased, a possible function is:

\mathbf{I(s) = 0.1s + 2500}

This is so, because 2500 is greater than 2000

When the commission rate is decreased, a possible function is:

\mathbf{I(s) = 0.05s + 2000}\\

This is so, because 0.05 is less than 0.1

So, the possible functions in the two scenarios are:

\mathbf{I(s) = 0.1s + 2500} and \mathbf{I(s) = 0.05s + 2000}\\

See attachment for the graphs of both functions

Read more about linear equations at:

brainly.com/question/21981879

5 0
2 years ago
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