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svet-max [94.6K]
3 years ago
9

12) As of August, 2011, Russia has had 21 rocket launch failures out of 743 total launches. To the nearest whole number, how man

y failures can be expected from the next 800 launches?
23
800
743
44
16,800
Mathematics
1 answer:
bogdanovich [222]3 years ago
5 0

Answer:

23

Step-by-step explanation:

It is given that, in Russia there are 21 rocket launch failures out of 743 total launches. We need to find no of failures for the next 800 launches.

21 rocket = 743 launches

1 launch = \dfrac{21}{743}\ \text{failures}

For 800 launches,

=\dfrac{21}{743}\ \text{failures}\times 800\\\\=22.611\ \text{failures}

or

= 23 failures

So, there are 23 failures in next 800 launches.

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<span>9 tenths </span>
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2 years ago
PLEASE ANSWER THE QUESTION IN THE PICTURE BELOW
vekshin1

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Answer:

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Step-by-step explanation:

The area is given by the formula ...

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The area of the triangle is 12 square inches.

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<em>Comment on the problem</em>

Since you are given the base and height, we presume you are intended to use the formula above. You are also given all three side lengths. If you use the appropriate formula with those, you find the area is about 15.6 square inches. (The height of this triangle is actually closer to 5.2 inches.)

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Step-by-step explanation:

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3 years ago
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Andrej [43]

Answer:

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Step-by-step explanation:

The total area of the box is the sum of the areas of all faces of the box. The top, bottom, front, and back faces are rectangles 18 in long. The end faces each consist of a rectangle and a triangle. We can compute the sum of these like this:

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2 years ago
What is the x-intercepts of y= -2(x-3)[2]+2?
mrs_skeptik [129]

Answer: (x,y)=(14/4,0)

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8 0
3 years ago
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