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Bumek [7]
3 years ago
10

A bag contains 12 counters. 7 of them are white. A counter is taken at random and not replaced. A second counter is taken out of

the bag at random. Calculate the probability that only one of the two counters is white​
Mathematics
1 answer:
grandymaker [24]3 years ago
8 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ First calculate how many counters are 'not white'

12 - 7 = 5

We have 5 counters that are 'not white'

The probability of taking a white counter the first time is 7/12

For the next pick, there would be 1 less of the total counters as it is not being replaced

The probability of then taking a 'not white' counter is 5/11

The other way you could still get one white counter is:

The first counter (non white) probability would be 5/12

The second counter (white) probability would be 7/11

Multiply these values:

7/12 x 5/11 = 35/132

5/12 x 7/11 = 35/132

Add these two values together:

35/132 + 35/132 = 70/132

Your answer is 70/132

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Which is the completely factored form of the following equation?<br><br> 4a4b2−21a2b+5=0
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The completely factored equation is (a²b - 5)(4a²b - 1)

<h3>How to factor equation?</h3>

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let's expand the equation

Therefore,

4a⁴b² - 21a²b + 5 = 0

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Rearrange the equation

4a⁴b² - a²b  - 20a²b + 5 = 0

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Suppose that y is directly proportional to x, and y = 150 when x = 15. What is the constant of proportionality?
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We are to find the constant of proportionality.

According to the given information, we can write

y\propto x\\\\\Rightarrow y=kx~~~~~~~~~~~~~~~~[\textup{where k is the constsnt of propotionality}].

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