The answer is 1.4 I just too the test
Answer:
The probability that components #1 and #2 fail, and at least one of components #3 and #4 fails is 0.031875
Step-by-step explanation:
Let's define the following events,
F1: Component #1 fails
F2: Component #2 fails
F3: Component #3 fails
F4: Component #4 fails
We are looking for the following probability
P[(F1∩F2)∩(F3∪F4)]
using distributive laws we have
P[(F1∩F2)∩(F3∪F4)] = P[(F1∩F2∩F3)∪(F1∩F2∩F4)] = P(F1∩F2∩F3) + P(F1∩F2∩F4) - P(F1∩F2∩F3∩F4) = P(F1)P(F2)P(F3) + P(F1)P(F2)P(F4) - P(F1)P(F2)P(F3)P(F4) = (0.25)(0.25)(0.3) + (0.25)(0.25)(0.3) - (0.25)(0.25)(0.3)(0.3)=0.031875
by the assumption of independence (the components fail independently) and because P(F1) = P(F2) = 0.25, P(F3) = P(F4) = 0.3
Answer:
I gotchu
b. x-4
Step-by-step explanation:
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