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4 years ago

Points c, a and b are collinear. Which of the following are opposite rays

Mathematics

1 answer:

Fiesta28 [93]4 years ago

3 0

Ca and ab i think because their rays ar epointing in opposite directins

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What is the slope of the line through (-1,4) and (5,2)

butalik [34]

Answer:

Slope (m) = $-\frac{1}{3}$

Step-by-step explanation:

Use the following equation:

Slope $(m) = \frac{y_2 - y_1}{x_2 - x_1}$

Let:

$(x_1 , y_1) = (-1 , 4)\\(x_2 , y_2) = (5 , 2)$

Plug in the corresponding numbers to the corresponding variables:

$m = \frac{2 - 4}{5 - (-1)} = \frac{2 - 4}{5 + 1} = \frac{-2}{6}$

Simplify. Divide common factors from both the numerator and denominator:

$\frac{(-\frac{2}{6})}{\frac{2}{2} } = -\frac{1}{3}$

$-\frac{1}{3}$ is your answer.

8 0

3 years ago

Let R be the region in the first quadrant bounded by the graphs of y =x^2 and y=2x, as shown in the figure above. The region R i

Kobotan [32]

Answer:

The area between the two functions is approximately 1.333 units.

Step-by-step explanation:

If I understand your question correctly, you're looking for the area surrounded by the the line y = 2x and the parabola y = x², (as shown in the attached image).

To do this, we just need to take the integral of y = x², and subtract that from the area under y = 2x, within that range.

First we need to find where they intersect:

2x = x²

2 = x

So they intersect at (2, 4) and (0, 0)

Now we simply need to take the integrals of each, subtracting the parabola from the line (as the parabola will have lower values in that range):

$a = \int\limits^2_0 {2x} \, dx - \int\limits^2_0 {x^2} \, dx\\\\a = x^2\left \{ {{x=2} \atop {x=0}} \right - \frac{x^3}{3}\left \{ {{x=2} \atop {x=0}} \right\\\\a = (2^2 - 0^2) - (\frac{2^3}{3} - \frac{0^3}{3})\\\\a = 2^2 - \frac{2^3}{3}\\a = 4 - 8/3\\a \approx 1.333$

So the correct answer is C, the area between the two functions is 4/3 units.

3 0

3 years ago

Can someone answer this for me (number 7 with quadratic equations algebraically)

s2008m [1.1K]

X1= 7
x2 = -1
I offer you to download All in one calculator.

3 0

3 years ago

A word processor that was purchased for $600

klasskru [66]

The slope of the graph shows the rate of change, or, in this case, the rate of depreciation, which you are told is $100 per year. So, depending upon the units used in your graph, the slope will be 100/1, and since it is a decrease as the years increase, it will have a negative slope, i.e. -100/1.

Or, if you had drawn your graph with units of $100 dollars on the y-axis, then you might say that the slope was -1 / 1.

The corresponding formula would of course be

y = 600 - 100t

where y = value after t years, and (if you are into calculus) differentiating would give you

slope = dy/dt = -100

<span>as noted above.</span>

4 0

3 years ago

Solve for x: 3-(2x-5)<-4(x+2)

andriy [413]

3-(2x-5)<-4(x+2)

8-2x<-8-4x

16<-2x

-8 > x. or equivalently x<-8

3 0

4 years ago