Answer:
- A. 5 to the power of negative 5 over 6
Step-by-step explanation:
so, 7 is neutral anything past 7 is considered basic.
answer: <em>a water and ammonia solution with a pH of 11 (very basic).</em>
<em />any number under 7 is acidic and of course there are different degrees of acidic just like there are different degrees of basicity.
______________________________________________________________
- stomach's digestive juices, would be considered very acidic
-apple juice is also acidic but not as acidic like stomach juices.
- grape juice, is becoming less acidic.
________________________________________________________________
Hopefully this helped and good luck.
A line passes throught the origin (-1, 1) and (4, n). Find the value of n. enter the correct answer in the box. I'd say (4, -2)
If I'm wrong sorry. If I'm correct May I Have Brainliest? <3
Answer:
(-9, -5)
Step-by-step explanation:
Ok, so when you move an image to the right, you are moving along the x-axis, and when you move up, you are moving up the y-axis. So if the altered image is (x,y) and the values are (-5, -1), you reverse what has been done to the image. In this case, since we moved to the right 4 units, we know that means we added 4 to x, so we subtract 4 to get -9. And then, for the y-value, because we added 4, we do the opposite, and subtract 4 to get -5. So the pre-image should be (-9, -5)
Answer:
Yes, an arrow can be drawn from 10.3 so the relation is a function.
Step-by-step explanation:
Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.
The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.
In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.
However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.