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N76 [4]
3 years ago
7

Find a counterexample to show that the statement is false. Assume all sets are subsets of a universal set U = {1, 2, 3, 4, 5}. (

Enter your answers for A, B, and C in roster notation as a comma-separated list of sets. Enter EMPTY or ∅ for the empty set.)For all sets A, B, and C,A ∪ (B − C) = (A ∪ B) − (A ∪ C).
Mathematics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

For subsets A={1,2},B={2,3},C={1,2 5} of U = {1, 2, 3, 4, 5}.

A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

Step-By-Step Explanation:

U = {1, 2, 3, 4, 5}.

A={1,2}

B={2,3}

C={1,2 5}

For the Left Hand Side

B-C={3}

A ∪ (B − C)= {1,2} ∪ {3} ={1,2,3}

Likewise, the Right Hand Side:

(A ∪ B)={1,2,3}

(A ∪ C)={1,2,5}

(A ∪ B)- (A ∪ C)= {1,2,3}-{1,2,5}={3}

Since, {1,2,3} ≠ {3}, A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

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Ben walks 25 miles from home to work. If he walks the first 5 miles in 1 hour, the second 5 miles in 1.4 hours, the third 5 mile
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<u>Answer:</u>

The total time taken to complete 25 miles is 7.6 hours.

Solution:

Ben walks 5 miles in 1 hour,

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Third 5 miles in 1.7 hours,

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So he walked total 20 miles in (1+1.4+1.7+1.8) hours = 5.9 hours = 6 hours (approximately)

So his average speed is \left(\frac{20}{6}\right) miles/hours = 3.33 miles/hours.  

i.e. he travels 3.3 miles in 1 hour,

Then, he travels 1 miles in \left(\frac{1}{3.3}\right) hours

Hence the total time he will take to walk 25 miles is \left(25 \times\left(\frac{1}{3.3}\right)\right) \text { hours }\Rightarrow \left(\frac{25}{3.3}\right) \text { hours } = 7.5757 hours

That is approximately 7.57 or 7.6 hours.

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