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svlad2 [7]
3 years ago
9

A mistake was made in mixing the lemonade— PLEASE HELP!!

Mathematics
1 answer:
beks73 [17]3 years ago
4 0

Answer:

Part A:

4 + x = y

0.5*4 + 1*x = 0.7*y

x = 8/3\ quarts\ of\ 100\%\ solution

y = 20/3\ quarts\ of\ 70\%\ solution

Part B:

x + y = 10

2x + 3y = 23

x = 7 and y = 3

Step-by-step explanation:

Part A:

The inicial concentration of the lemonade is 50%, and the volume is 4 quarts, and we will add x quarts of a lemonade with a concentration of 100%, so the total volume will be y, and the concentration will be 0.7, so we have that:

4 + x = y

0.5*4 + 1*x = 0.7*y

Using the value of y from the first equation in the second one, we have:

2 + x = 0.7*(4 + x)

2 + x = 2.8 + 0.7x

0.3x = 0.8

x = 8/3\ quarts

y = 4 + 8/3 = 20/3\ quarts

Part B:

If he shoots a total of ten targets, we can write the equation:

x + y = 10

Each stationary target is 2 points, and each moving target is 3 points, so if the total points is 23, we have:

2x + 3y = 23

If we subtract the second equation by two times the first one, we have:

2x + 3y - 2*(x + y) = 23 - 2*10

2x + 3y - 2x - 2y = 23 - 20

y = 3

x + 3 = 10 ⇒ x = 7

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