This is a simple programming question. To calculate the average of any two numbers, where one number is 1 and the other is n, simply add the two numbers and divide by 2. Therefore, the answer is:
<span>avg = (1 + n) / 2</span>
Answer:

Step-by-step explanation:
sin60° = 
tan60° = 
tan45° = 1
cos45° = 
(2sin60°)(3tan60°) - (4tan45°)(2cos45°)
now substitute the values of each trigonometrical angles






Let x% be the salt concentration of first solution.
Then in 8ml, amount of salt = 
Given that to this 8ml solution, 11ml solution of a 47% salt solution is mixed.
amount of salt in 11ml of 47% salt solution is
= 
So, total amount of salt in new mixture = 
But given that this new solution is a 43% salt solution.
Hence amount of salt in new mixture of (8+11)=19ml solution of 43% salt solution is 
Hence 
8x+517 = 817
8x=817-517 = 300
x= 300/8 = 37.5
Hence the salt concentration in the first solution is 37.5%
Solution:
<u>It should be noted:</u>
- Opposite sides of a rhombus are always equal.
- Opposite angles of a rhombus are always equal.
<u>Thus:</u>
- (-y - 10) = 90°
- 3z - 3 = 90°
- 4x - 2 = 90°
<u>Finding x:</u>
- 4x - 2 = 90°
- => 4x = 90 + 2
- => 4x = 92
- => x = 23
<u>Finding y:</u>
- (-y - 10) = 90°
- => -y - 10 = 90°
- => -y = 100
- => y = -100
<u>Finding z:</u>
- 3z - 3 = 90°
- => 3z = 90 + 3
- => 3z = 93
- => z = 31
Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx