4 would be your answer lol
4/3+6/9-7/3=12/9+6/9-21/9=18/9-21/9= -3/9= -1/3
Logbx+logby-logbz
=logb(x*y)/z if b is the base of log.
There are two properties that you can apply to get the correct answer.
logb(x*y)=logbx+logby if b is the base of log.
logb(x/y)=logbx-logby if b is the base of log, so the correct answer for logbx+logby-logbz=logb(x*y)/z. Hope it help!
Answer: The tangent of the larger acute angle is 4/3 or 1⅓
Step-by-step explanation: if the sides of the right angled triangle are given as 3, 4 and 5 respectively, then the hypotenuse is 5 and the longer of the other two sides is 4. The angle facing the side measuring 4 is your reference angle, and that is the larger of the other two acute angles (see attachment)
Tan X = opposite/hypotenuse
Tan X = 4/3
Tan X = 1⅓