Answer:
Critical value f(1)=2.
Minimum at (1,2), function is decreasing for
and increasing for 
is point of inflection.
When 0<x<3, function is concave upwards and when x>3, , function is concave downwards.
Step-by-step explanation:
1. Find the domain of the function f(x):

2. Find the derivative f'(x):

This derivative is equal to 0 at x=1 and is not defined at x=0. Since x=0 is not a point from the domain, the crititcal point is only x=1. The critical value is

2. For
the derivative f'(x)<0, then the function is decreasing. For
the derivative f'(x)>0, then the function is increasing. This means that point x=1 is point of minimum.
3. Find f''(x):



When f''(x)=0, x=3 and
When 0<x<3, f''(x)>0 - function is concave upwards and when x>3, f''(x)>0 - function is concave downwards.
Point
is point of inflection.
Answer:
C.{-1,0,1,2}
Step-by-step explanation:
basically you would do length x width
5x and x
6 and 4
It is not recommended that points be marked with X, let's marked with C(6,6)=(Xc,Yc)
The coordinates of the point C(Xc,Yc) which belongs to the line AB and divides line AB in a ratio m : n = 1 : 2 or m/n=1/2 are get it with following formula
Xc=(Xa+(m/n)Xb) / (1+(m/n)) and Yc=(Ya+(m/n)Yb) / (1+(m/n))
We have A(2,2)=(Xa,Ya) and B(14,14)=(Xb,Yb)
When we replace given coordinates we get
Xc=(2+(1/2)*14) / (1+(1/2)) = (2+7) /(3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Xc=6
Yc=(2+(1/2)*14) / (1+(1/2)) = (2+7) / (3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Yc=6
C(Xc,Yc)=(6,6)
Good luck!!!