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alex41 [277]
3 years ago
8

twenty seven inches is the same as 2 feet 3 inches. What is your height in feet and inches 48 inches tall?

Mathematics
1 answer:
aalyn [17]3 years ago
4 0
27in = 2ft 3 inches
1ft=12in
48/12=4ft

Your height (48 inches) is 4 feet
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David's car could cover one lap of the Indy 500 in about 90 seconds. Chris' car could cover one lap in about 54 seconds. If both
kramer

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Step-by-step explanation:

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3 years ago
Hard question but would help me out
Alekssandra [29.7K]

Answer:

Critical value f(1)=2.

Minimum at (1,2), function is decreasing for 0 and increasing for x>1.

\left(3,\dfrac{4}{\sqrt{3}}\right) is point of inflection.

When 0<x<3, function is concave upwards and when x>3, , function is concave downwards.

Step-by-step explanation:

1. Find the domain of the function f(x):

\left\{\begin{array}{l}x\ge 0\\x\neq 0\end{array}\right.\Rightarrow x>0.

2. Find the derivative f'(x):

f'(x)=\dfrac{(x+1)'\cdot \sqrt{x}-(x+1)\cdot (\sqrt{x})'}{(\sqrt{x})^2}=\dfrac{\sqrt{x}-\frac{x+1}{2\sqrt{x}}}{x}=\dfrac{2x-x-1}{2x\sqrt{x}}=\dfrac{x-1}{2x^{\frac{3}{2}}}.

This derivative is equal to 0 at x=1 and is not defined at x=0. Since x=0 is not a point from the domain, the crititcal point is only x=1. The critical value is

f(1)=\dfrac{1+1}{\sqrt{1}}=2.

2. For 0 the derivative f'(x)<0, then the function is decreasing. For x>1, the derivative f'(x)>0, then the function is increasing. This means that point x=1 is point of minimum.

3. Find f''(x):

f''(x)=\dfrac{(x-1)'\cdot 2x^{\frac{3}{2}}-(x-1)\cdot (2x^{\frac{3}{2}})'}{(2x^{\frac{3}{2}})^2}=

=\dfrac{2x^{\frac{3}{2}}-2(x-1)\cdot \frac{3}{2}x^{\frac{1}{2}}}{4x^3}=\dfrac{2x^{\frac{3}{2}}-2\cdot\frac{3}{2}x^{\frac{3}{2}}+ 2\cdot\frac{3}{2}x^{\frac{1}{2}}}{4x^3}=

=\dfrac{-x+3}{4x^{\frac{5}{2}}}.

When f''(x)=0, x=3 and f(3)=\dfrac{3+1}{\sqrt{3}}=\dfrac{4}{\sqrt{3}}.

When 0<x<3, f''(x)>0 - function is concave upwards and when x>3, f''(x)>0 - function is concave downwards.

Point \left(3,\dfrac{4}{\sqrt{3}}\right) is point of inflection.

4 0
4 years ago
Given the relation {(2, 3), (-2, 2), (1, 5), (0, -1)}, state the domain.
MAVERICK [17]

Answer:

C.{-1,0,1,2}

Step-by-step explanation:

3 0
3 years ago
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How would I complete this?
Nat2105 [25]

basically you would do length x width

5x and x

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7 0
4 years ago
Line AB is a directed segment with endpoints A(2,2) and B(14,14). In two or more complete sentences, explain how you would verif
Kisachek [45]

It is not recommended that points be marked with X, let's marked with C(6,6)=(Xc,Yc)

The coordinates of the point C(Xc,Yc) which belongs to the line AB and divides line AB in a ratio m : n = 1 : 2 or m/n=1/2 are get it with following formula

Xc=(Xa+(m/n)Xb) / (1+(m/n)) and Yc=(Ya+(m/n)Yb) / (1+(m/n))

We have A(2,2)=(Xa,Ya) and B(14,14)=(Xb,Yb)

When we replace given coordinates we get

Xc=(2+(1/2)*14) / (1+(1/2)) = (2+7) /(3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Xc=6

Yc=(2+(1/2)*14) / (1+(1/2)) = (2+7) / (3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Yc=6

C(Xc,Yc)=(6,6)

Good luck!!!



4 0
3 years ago
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