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Alex73 [517]
3 years ago
11

Write the rule for finding the coordinates of a point’s 90⁰ clockwise rotation about the origin.

Mathematics
1 answer:
malfutka [58]3 years ago
8 0
Unless told otherwise, the center ofrotation<span> is the </span>origin<span> (0, 0).</span>
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Simplify.<br><br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B8%2B6%5E2%7D%7B11%7D%20" id="TexFormula1" title=" \frac{8+6^2}{
Romashka [77]
\frac{8 + 6^2}{11} + 7 \times 2 \\ \\  \frac{8 + 36}{11} + 7 \times 2 \ / \ simplify \\ \\  \frac{44}{11} + 7 \times 2 \ / \ simplify \\ \\ 4 + 7 \times 2 \ / \ simplify \\ \\ 4 + 14 \ / \ simplify \\ \\ 18 \ / \ simplify \\ \\

The final result is 18.
4 0
3 years ago
A tire company finds that the lifespan for one brand of its tires is normally distributed with a mean of 47,500 miles and a stan
Illusion [34]

Answer:

42580 miles

Step-by-step explanation:

Mean = \mu = 47500

\sigma = 3000

The manufacturer does not want to replace more than 5% of the tires

P(X\leq x)=5\%

P(\frac{x-\mu}{\sigma}\leq \frac{x-47500}{3000})=0.05

By using normal table values :

\frac{x-47500}{3000}=-1.64

x=(-1.64 \times 3000)+47500

x=42580

Hence the approximate number of miles for the warranty is 42580 miles

6 0
3 years ago
Please answer question 4
olasank [31]
#4)
cross multiply
2(8x+10) = 4 * 5x
16x + 20 = 20x
4x = 20
  x = 5
3 0
3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
3 years ago
Please help me<br><br>I will give you 20 points ​
otez555 [7]
Your dividing number for both is by 8. Since 8 hours divided by 8 equals 1. You will do the same to the top and get an answer of 25 miles!!
7 0
2 years ago
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