Answer:see explanation
Explanation:
Hello, from your question I see that you need a program which based on countNum's value prints ready then all the numbers to 1 and finally go!, I'd appreciate if you provided information about the numbers after the example you gave as I do not know if they are to be printed too.
The solution I provide includes the countdown to 1 printing newline after each number and text. Try it out!
#include <stdio.h>
int main(void)
{
int countNum;
int i;
countNum = 22;
for ( i = countNum; i > 0; i--) {
if (i == countNum){
printf("Ready!\n");
}
printf("%d\n",i);
}
printf("Go!\n");
return 0;
}
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Answer:
def sum_numbers(value_list):
total = 0
for n in value_list:
if type(n) == int or type(n) == float:
total += n
return total
Explanation:
Create a function called sum_numbers that takes one parameter, value_list
Initialize the total as 0
Create a for loop that iterates through the value_list
Inside the loop, check the type of the elements. If they are either int or float, add them to total.
When the loop is done, return the total
A graphics processing unit. (GPU)
