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lyudmila [28]
2 years ago
12

A fair coin is flipped four times. Find the probability that exactly two of the flips will turn up as heads.​

Mathematics
1 answer:
velikii [3]2 years ago
5 0

Answer:

%50 if will be on heads twice

Step-by-step explanation:

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Hugh poured 100 kilograms of water into 10 kg of salt.
Leokris [45]

Answer:

110, 9.1. The total weight of the salt solution is the weight of water plus the weight of salt. So he made 100+10=110 kg of salt solution.

Step-by-step explanation:

7 0
2 years ago
Solve a,b,c,d please
sdas [7]
For each, replace x with the number in the parenthaseses

a.
f(2.5)=\frac{1}{2.5-2}=\frac{1}{0.5}=2


b.
f(1.75)=\frac{1}{1.75-2}=\frac{1}{-0.25}=-4


c.
f(2)=\frac{1}{2-2}=\frac{1}{0}=undefined
division by 0 is not allowed so it is undefined at the point


d. because division by 0 is not allowed
7 0
3 years ago
a certain pharmaceutical company know that, on average 4% of a certain type of pill has an ingredient that is below the minimum
FinnZ [79.3K]

Using the binomial distribution, it is found that there is a 0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

For each pill, there are only two possible outcomes, either it is acceptable, or it is not. The probability of a pill being acceptable is independent of any other pill, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The sample has 20 pills, hence n = 20.
  • 100 - 4 = 96% are acceptable, hence p = 0.96

The probability that <u>fewer that 5 in a sample of 20 pills</u> will be acceptable is:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.96)^{0}.(0.04)^{20} = 0

P(X = 1) = C_{20,1}.(0.96)^{1}.(0.04)^{19} = 0

P(X = 2) = C_{20,2}.(0.96)^{2}.(0.04)^{18} = 0

P(X = 3) = C_{20,3}.(0.96)^{3}.(0.04)^{17} = 0

P(X = 4) = C_{20,4}.(0.96)^{4}.(0.04)^{16} = 0

0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

A similar problem is given at brainly.com/question/24863377

8 0
2 years ago
Find the missin value in the ratio table
Snowcat [4.5K]

20

U have to divide it by 3 the ratio is 1:3

4 0
2 years ago
Work out m and c for the line: y -4x= − 1
Lelu [443]

Step-by-step explanation:

y = 4x - 1 \\ m = 4 \\ c =  - 1

8 0
2 years ago
Read 2 more answers
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