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Anettt [7]
3 years ago
7

A hockey game had 2,058 fans Friday night. The baseball game has 1,300 fans that night. How many more fans were at the hockey ga

me?
Mathematics
2 answers:
taurus [48]3 years ago
6 0

Subtract the number at the baseball game from the hockey game:

2058 - 1300 = 758

There was 758 more people at the hockey game.

Varvara68 [4.7K]3 years ago
5 0

Answer:

758 more fans were there

Step-by-step explanation:

Difference = Hockey fans - Baseball fans

= 2058 - 1300

= <u>758 </u>

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What is the equation of the line that passes through the point (-4, 2) and has a slope of 1/4?​
natulia [17]

Answer:

y = 1/4x + 3

Step-by-step explanation:

m = 1/4, (-4,2)

y -2 = 1/4(x - - 4)

y - 2 = 1/4 (x + 4)

y - 2 = 1/4x + 1

y = 1/4x + 1 + 2

y = 1/4x + 3

5 0
3 years ago
Pre-calc, Review the table of values for function h(x). (image attached)
GalinKa [24]

Answer:

\lim_{x \to 10^+} h(x) = 18.5

Step-by-step explanation:

As x approaches 10 from the right side, h(x) approaches 18.5 but never touches it.

3 0
3 years ago
Trying to finsh fast so help please
max2010maxim [7]

Answer:

A-B

Step-by-step explanation:

5 0
3 years ago
During a baseball game, a food stand sells popcorn for $2.50 and hotdogs for $3 each. If at the end of the game, the stand made
nasty-shy [4]
Let
x-------> bags of <span>popcorn
</span>y-------> bags of hotdogs

we know that
2.50x+3y=200-------> equation 1
x=2y--------> equation 2

substitute 2 in 1

2.50*[2y]+3y=200--------> 5y+3y=200------> 8y=200-----> y=200/8
y=25
x=2y-----> x=2*25-----> x=50

the answer is
50 bags of popcorn
25 bags of hotdogs<span />
5 0
3 years ago
What is the height of an equilateral triangle if the sides are 10
4vir4ik [10]

Answer:

The height of the equilateral triangle is 5\sqrt{3}\ units

Step-by-step explanation:

we know that

An equilateral triangle has three congruent sides, and three congruent angles that each measure 60 degrees

To find out the height of an equilateral triangle, apply the Pythagoras Theorem in the right triangle ABD

Remember that the height of an equilateral triangle bisects the base.

see the attached figure to better understand the problem

AB^2=AD^2+BD^2

substitute the given values

10^2=5^2+BD^2

Solve for BD

100=25+BD^2

BD^2=100-25

BD^2=75

BD=\sqrt{75}\ units

simplify

BD=5\sqrt{3}\ units`

therefore

The height of the equilateral triangle is 5\sqrt{3}\ units

7 0
3 years ago
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