Answer:
−7r^(2)+12r+10x−18
Step-by-step explanation:
Grab the original equation: 10x+7r−r^(2)−6r^(2)−18+5r
For subtraction bits, treat them as negatives: 10x+7r+−r^(2)+−6r^(2)+−18+5r
Combine like terms: (−r^2+−6r^2)+(7r+5r)+(10x)+(−18)
Simplify that, and you get your final answer: −7r^(2)+12r+10x+−18
QRST is a rhombus
Let’s look at the diagonals
Length QS = sr(4^2 + 0) = 4
Length RT = sr(0 + 6^2) = 6
This means it cannot be a square or rectangle as they both have equal length diagonals.
QS is horizontal (y values same)
RT is horizontal (x values same)
This means it is a rhombus because diagonals are perpendicular and different lengths.
Squares have perpendicular diagonals of same length
Rectangles have diagonals of same length but not perpendicular
I think the answer might be 35!
Answer:
x=7.5
Step-by-step explanation:
To solve this, cross multiply
3/4=x/10
4*x=3*10
4x=30
Divide by 4 on both sides
x=7.5
Hope this helps! :)
