1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Virty [35]
3 years ago
8

Nancy's 50 meter freestyle swim time was 28.004 seconds Betty's 50 meter freestyle swim time was 27.949 seconds what's the diffe

rence between the times
Mathematics
2 answers:
fredd [130]3 years ago
7 0
28.004 - 27.949 = 0.055 seconds

The difference between the times is 0.055 seconds.
blagie [28]3 years ago
6 0
28.004 - 27.949 = 0.055 seconds
You might be interested in
A rectangle has vertices at these coordinates.
GalinKa [24]
It would be (4, 5) because add the 2nd and third than you get (4, 5)
7 0
3 years ago
Read 2 more answers
ONLY answer if you know! Which of the following will have a negative result? (1 point)
Nastasia [14]
The negative would be 12-14 witch = -2
4 0
3 years ago
A plane left 30 minutes late than its schedule time and in order to reach the destination 1500 km away in time it had to increas
schepotkina [342]
Let x= the usual speed
1500/x would equal how long it usually took the plane to read the destination
1500/(x+100) would equal how long it would take the plane now
So\frac{1500}{x} - \frac{1500}{x+100} =  \frac{1}{2} because it would lose 30 minutes already
Simplify:
\frac{1500(x+100)-1500x}{x(x+100)} =  \frac{1}{2}
\frac{1500x+150000-1500x}{x^2+100x} = \frac{1}{2}
\frac{150000}{x^2+100x} = \frac{1}{2}
\frac{300000}{x^2+100x} =1
300000= x^{2} +100x

x^2+100x-300000=0

x^2+600x-500x-300000=0

x(x+600)-500(x+600)

(x-500)(x+600)

x=500, x \neq -600


The usual speed was 500 hm/hr

7 0
3 years ago
A manufacturing firm just received a shipment of 20 assembly parts, of slightly varied sizes, from a vendor. The manager knows t
kati45 [8]

Answer:

Step-by-step explanation:

Given that a manufacturing firm just received a shipment of 20 assembly parts, of slightly varied sizes, from a vendor. The manager knows that there are only 15 parts in the shipment that would be suitable.

a) The probability that the first part is suitable.

= no of suitable/total = \frac{15}{20} =0.75

b) the probability that the second part is also suitable/first part was suitable

= Prob that first two parts suitable/Prob first part suitable

= \frac{\frac{15C2}{20C2} }{0.75} \\= 0.7368

c) If the first part is suitable, find the probability that the second part is not suitable

= Prob I part suitable and second not suitable/Prob first part suitable

= \frac{\frac{15}{20}\frac{5}{19}  }{0.75} \\= 0.2632

8 0
3 years ago
What is the slope of the line that goes through points (−3,6) and (8,9) ?
Pie

Answer:

the answer is

Step-by-step explanation:

3/11

the formula is y2-y1 / x2-x1

4 0
3 years ago
Other questions:
  • What is the common difference of an arithmetic sequence defined by the formula an=6n+3?
    7·2 answers
  • When writing an equation how would I do that and how would I put it into a table of values chart
    7·1 answer
  • Please Help Me<br> chdhjdghfjfhdj
    8·1 answer
  • The weights of ice cream cartons are normally distributed with a mean weight of 1313 ounces and a standard deviation of 0.50.5 o
    14·1 answer
  • A farmer uses a lever to move a large rock. The force required to move the rock varies inversely with the distance from the pivo
    10·1 answer
  • Do przygotowania ćwierć litra soku potrzebne są 4 marchewki. Ile marchewek potrzeba żeby otrzymać pół litra soku, litr soku, 2li
    10·1 answer
  • An electronics store purchased a CD player at a wholesale price of 60$ and then sold it at a 40 percent discount off the origina
    7·1 answer
  • Hi guys can you please help me
    14·1 answer
  • If anybody can solve these two I’ll give you 20
    11·2 answers
  • Help me please! <br> I need to type the word but I don’t know what it is
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!