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3 years ago

How much larger is a meter that a centimeter

Mathematics

2 answers:

snow_lady [41]3 years ago

8 0

A meter is 100 times larger than a centimeter

True [87]3 years ago

3 0

Answer:

A meter is 100 times larger than a centimeter

Step-by-step explanation:

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The age difference between the two brothers is 5. 7 years later, the age of the elder brother will be 3 times bigger than the ag

saw5 [17]

Answer:

<em><u>y = 4 and x = 9</u></em>

Step-by-step explanation:

I hope this is correct

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3 years ago

Guysss I need help ASAPPPP I need to get this done todayyy :(((

PIT_PIT [208]

Answer:

see below

Step-by-step explanation:

t = 7m

Let m = 6

t = 7*6 = 42

Let m = 8

t = 7*8

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3 years ago

Read 2 more answers

If the Alpha company is 79% staffed and the Beta company is only 62% staffed, what is the relative change of staffing from the A

sweet [91]

Answer:

27.41%

Step-by-step explanation:

Data provided in the question

The staffed of Alpha company = 79%

The staffed of Beta company = 62%

Based on the above information, the relative change of staffing from Alpha to beta company is

As we know that

$\bold {\ Relative \ change = \frac{\alpha- \beta }{\beta }}$

$= \frac{(79 -62)}{62} \% \\\\= \frac{17}{62} \times 100\\\\=0.2741 \times 100\\\\=27.41\ \%$

By applying the above formula we can get the relative change and the same is to be applied so that the correct percentage could come

5 0

4 years ago

The number of cartons of apples sold at a store each day for eight days is shown. 30 , 40 , 51 , 30 , 34 , 20, 30, 45 Determine

nikitadnepr [17]

Answer:

Mean = 35

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

(30 + 34) /2 = 32

Mode = 30 ( most frequent)

Range = (51 - 20) = 31

Mean = 72

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

4th + 5term = (72 + 77) /2 = 74.5

Mode = 72 ( most frequent)

Range = (90 - 48) = 42

Step-by-step explanation:

Given :

1.)

Data: 30 , 40 , 51 , 30 , 34 , 20, 30, 45

Rearranged data : 20, 30, 30, 30, 34, 40, 45, 51

Mean = ΣX / n = 280 / 8

Mean = 35

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

(30 + 34) /2 = 32

Mode = 30 ( most frequent)

Range = (51 - 20) = 31

2.)

90 , 72 , 48 , 84 , 77 , 72, 50, 83

Rearranged data : 48, 50, 72, 72, 77, 83, 84, 90

Mean (m) = ΣX / n = 576 / 8

Mean = 72

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

4th + 5term = (72 + 77) /2 = 74.5

Mode = 72 ( most frequent)

Range = (90 - 48) = 42

6 0

3 years ago

Each employee receives a 5% raise find the mean median and mode of the data with the race how does this incurs affect the mean m

marshall27 [118]

Answer:

Step-by-step explanation:

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3 years ago