BRAINLIEST TO THE FIRST PERSON TO ANSWER!!The expression on the left side of an equation is shown below.

Which answer does NOT correctly describe the graph of y = 5x + 12?

Svetlanka [38]

<h2>Answer</h2>

2. The Graph Contains The Point (5, 12)

<h2>Explanation</h2>

Remember that in a linear function of the form $y=mx+b$ , $m$ is the slope/rate of change of the line and $b$ is the y-intercept.

From our equation we can infer that $b=12$ , so the y-intercept of our graph is 12 units above the origin on the point (0, 12). Therefore, choice 2 correctly describe the graph of y = 5x + 12

We can also infer that $m=5$ , so the slope of our line is 5, which is constant, so our line has a constant rate of change. Also, since every integer can be written as a fraction with denominator 1, we can write our slope as $m=\frac{5}{1}$ . Therefore, choices 1 and 2 correctly describe the graph of y = 5x + 12.

Now, remember that any point on the plane has coordinates $(x,y)$ , so, to check if a point is on a line, we just need to replace the $x$ and $y$ values in the line equation and check if the equation holds. Our point is (5, 12), so x = 5 and y = 12. Lets replace the values in our line:

$y=5x+12$

$12=5(5)+12$

$12=25+12$

$12\neq 37$

Since the equation equation doesn't hold (12 is not equal 37), we can conclude that the graph doesn't contain the point (5, 12). Therefore, choice 2 does NOT correctly describe the graph y = 5x +12.