3 years ago

8th grade math probability

Mathematics

1 answer:

kari74 [83]3 years ago

3 0

In problem 16 I think the answers is b

You might be interested in

Of new calculators tested,8 were defective and 42 passed inspection. What ratio compares the number of defective calculators to

sesenic [268]

The number of new calculators tested was 50 . . . 8 were bad and 42 were good.

The ratio of defective ones to new ones tested is 8:50 or 4:25 or 16% .

4 0

3 years ago

Read 2 more answers

Pls and thanks help me

PIT_PIT [208]

She spent 200 minutes

6 0

2 years ago

Question<br> What is the factored form of this polynomial?<br> p(x) = x + 7x2 + 4x - 12

Soloha48 [4]

Answer:

^(3)+7x^(2)+4x-12

Step-by-step explanation:

8 0

3 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

5 0

3 years ago

A line that intersects two or more lines is called a parallel line true or false

Irina18 [472]

Answer:

False

Step-by-step explanation:

Parallel lines never touch

6 0

3 years ago