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sesenic [268]
3 years ago
6

Use the commutative and associative properties as needed to simplify the expression.(16+a)+15​

Mathematics
1 answer:
Serjik [45]3 years ago
8 0

Answer:The expression can be simplified in following steps;

Step-by-step explanation:

(16+a)+15=0

16+15+a=0

31+a=0

a=-31

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What is the answer?
g100num [7]
I'll tell you the answer but should I graph it, solve for x, solve for y, or what should I solve for?
3 0
3 years ago
5. If position of object x = 3 sinΘ – 7 cosΘ then motion of object is bounded between position.​
lesya692 [45]

9514 1404 393

Answer:

  ±√58 ≈ ±7.616

Step-by-step explanation:

The linear combination of sine and cosine functions will have an amplitude that is the root of the sum of the squares of the individual amplitudes.

  |x| = √(3² +7²) = √58

The motion is bounded between positions ±√58.

_____

Here's a way to get to the relation used above.

The sine of the sum of angles is given by ...

  sin(θ+c) = sin(θ)cos(c) +cos(θ)sin(c)

If this is multiplied by some amplitude A, then we have ...

  A·sin(θ+c) = A·sin(θ)cos(c) +A·cos(θ)sin(c)

Comparing this to the given expression, we find ...

  A·cos(c) = 3   and   A·sin(c) = -7

We know that sin²+cos² = 1, so the sum of the squares of these values is ...

  (A·cos(c))² +(A·sin(c))² = A²(cos(c)² +sin(c)²) = A²(1) = A²

That is, A² = (3)² +(-7)² = 9+49 = 58. This tells us the position function can be written as ...

  x = A·sin(θ +c) . . . . for some angle c

  x = (√58)sin(θ +c)

This has the bounds ±√58.

3 0
3 years ago
On the exam, Rebecca successfully created 20 out of 25 vases.
juin [17]

\text{Hello there! :]}

\large\boxed{125 \text { vases}}

\text{To solve, find the proportion of successes from the total:}\\\\20 / 25 = 4 / 5\\\\\text{Set up a proportion to find the # of vases necessary to complete 100 successfully:}\\\\\frac{20}{25}  = \frac{100}{x} \\\\\text{Cross multiply to solve:}\\\\20 * x = 100 * 25\\\\20x = 2500\\\\\text{Divide both sides by 20:}\\\\x = 125 \text{ vases}

7 0
3 years ago
Read 2 more answers
Factorise the following.​
zepelin [54]

Answer:

Step-by-step explanation:

i). \frac{48a^3}{6a}=\frac{6\times 8\times a\times a^2}{6a}

          =\frac{6a}{6a}\times 8a^2

          = 8a²

ii). \frac{72a^3b^4c^5}{8ab^2c^3} = \frac{8\times 9\times a\times a^2\times b^2\times b^2\times c^2\times c^3}{8ab^2c^3}

                = \frac{8ab^2c^3}{8ab^2c^3}\times 9a^2b^2c^2

                = 9a²b²c²

8 0
3 years ago
Please answer this question now
soldier1979 [14.2K]

Answer:

6 km

Step-by-step explanation:

You use Pythagoras

{QN}^2 = (PN)^{2}+(PQ)^{2} \\PQ = \sqrt{(QN)^{2}-(PN)^{2}  }\\ PQ = 6 km

7 0
4 years ago
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