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LiRa [457]
4 years ago
7

Guys please help me on this I’m so stuck

Mathematics
2 answers:
Sergio [31]4 years ago
7 0

Answer:

It is the third option

Step-by-step explanation:

ln(xy)=ln(x)+ln(y)

ln(x/y)=ln(x)−ln(y)

ln(xy)=yln(x)

use these three rules, first separate the fraction out to log(\log (x^2-6)^4 - \log \sqrt[3]{x^2+8} , then take the exponent and root out to make 4\log (x^2-6)- \frac{1}{3} \log x^2+8

padilas [110]4 years ago
7 0

Answer:

C

Step-by-step explanation:

log_{w} \frac{(x^2-6)^4}{\sqrt[3]{x^2+8} } = log_{w}(x^2-6)^4-log_{w}(x^2+8)^\frac{1}{3}=\\ \\=4log_{w}(x^2-6)-\frac{1}{3}log_{w}(x^2+8)

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The ordered pair (0,4) is a soultion of which system
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Substitute 0 for x and 5 for y in the first equation and then the second equation. Since 0 + 5 = 5 and -5*0 + 2*5 = 10 the answer </span>
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Step-by-step explanation:

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3 years ago
Given f(x) = the quantity of x plus 7, divided by 5, solve for f−1(3)
Debora [2.8K]
<span>f(x) = the quantity of x plus 7, divided by 5f(x)= \frac{x+7}{5}


</span>

To get the inverse of any function f(x) [ just make sure that it passes the horizontal line test] follow the steps:

- Solve for x, i.e separate x in one side and the other terms in the other side, included f(x).

- Swap x and f(x).

- The result is the inverse of the original function f^{-1}(x)



So that:

5*f(x)=x+7\\~\\~\\5f(x)-7=x\\~\\~\\Swap~now\\~\\~\\f^{-1}(x)=5x-7



and for the value of 3:

f^{-1}(3)=5(3)-7=15-7=8


I hope that helps!




6 0
4 years ago
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