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3 years ago

Can anyone help me with this question please? :( I’m stuck on this question!

Mathematics

1 answer:

Andrews [41]3 years ago

3 0

What is the question

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Vrite your definition of square numbers. Square numbers:

oksian1 [2.3K]

Answer:

Square numbers are numbers that have been multiplied by themselves.

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3 years ago

What negative number is the same distance as the number +4 explain graph both numbers on the number on the number line below

alina1380 [7]

The answer is negative 4...4 to 0 has the same distance as -4 to O

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4 years ago

If 5/8ths is equal to $531.25 what is the remaining portion of the number.

Nimfa-mama [501]

5/8 = .625
531.25 / .625 = 850
850 - 531.25 = $318.75

7 0

3 years ago

I have 86 chocolate chip cookies and 42 sugar cookies what is the greatest number of identical packages that I can make

baherus [9]

Step-by-step explanation:

Given that,

No. of chocolate chip cookies = 86

No. of sugar cookies = 42

We need to find the number of identical packages that I can make.

It means we need to find the HCF of these 2 number.

Prime factorization of 86 and 42 as follows :

86 = 2 x 43

42 = 2 x 3 x 7

HCF = 2

Hence, I can make 2 identical packages.

3 0

3 years ago

Read 2 more answers

Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =

Helen [10]

For the ODE

$ty'+2y=\sin t$

multiply both sides by t so that the left side can be condensed into the derivative of a product:

$t^2y'+2ty=t\sin t$

$\implies(t^2y)'=t\sin t$

Integrate both sides with respect to t :

$t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C$

Divide both sides by $t^2$ to solve for y :

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}$

Now use the initial condition to solve for C :

$y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}$

$\implies9=\dfrac4{\pi^2}(1+C)$

$\implies C=\dfrac{9\pi^2}4-1$

So the particular solution to the IVP is

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}$

$y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}$

6 0

3 years ago