Hey there!
150 = 8x + 6y
↠ 150 = 8x + 6(9)
↠ 8x + 6(9) = 150
↠ 8x + 54 = 150
SUBTRACT 54 to BOTH SIDES
8x + 54 - 54 = 150 - 54
CANCEL out: 54 - 54 because that gives you 0
KEEP: 150 - 54 because helps solve for x
↣150 - 54 = 96↢
NEW EQUATION: 8x = 96
DIVIDE 8 to BOTH SIDES
8x/8 = 96/8
CANCEL out: 8/8 because that gives you 1
KEEP: 96/8 because that gives the value of x
96/8 = x
x = 12
Answer: x = 12
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Answer: The answer is 6.
The number sentence is
3-3=0
10-4=6
So, 13-7=6
Step-by-step explanation:
To solve
, by making ten
First break 13 and write 
Then break 7 as 
Now to subtract 7 from 13,
Step 1. Subtract 3 (a part of 7), from 3(a part of 13) or cross 3 circles, then we have left 10-4

Step 2. Subtract 4 from 10 or cross 4 circles out of 10, we get 6.
The answer is 6.
There is a pattern of -2, -6, so the next number is 20.
All circles are similar because all circle have same shape.
However Two circles are congruent , if and only if their radii are congruent.
In our question we are asked when are all circles similar given if their radii are congruent.
So we can say this statement is false because no matter the radii are congruent or not , two or more circles are always similar because of their same shape no matter what the measure of their radii is. Only if we are asked when they are congruent, we will consider the radii part.
Answer is false.
Answer:
g(t) = 10000(0.938)^t
Step-by-step explanation:
Given data:
car worth is $10,000 in 2012
car worth is $8000 in 2014
let linear function is given as
P(t) = at + b
which denote the value of car in year t
take t =0 for year 2012
at t =0, 10,000 = 0 + b
we get b = 10,000
take t =2 for year 2014
at t =2, P(2) = 2a + b
8800 = 2a + 10,000
a = - 600
Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000
let the exponential function
where t denote t = 0 at 2012
putting t = 0 P(0) = 10,000 we get 10,000 = ab^0
a = 10,000
putting t = 2 p = 8800


b = 0.938
g(t) = 10000(0.938)^t