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3 years ago

What is the least common multiple of 8 and 10? Enter your answer in the box. _____

Mathematics

1 answer:

Vadim26 [7]3 years ago

6 0

40 is the LCM,

Hope it helps ❤️

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If you have work plz show it but I need help with this anyone?

inysia [295]

1) -31

2)-15

3)-13

4)-7

5) 32

6)-7

7)-23

8) 2

9) 9

10) 10

5 0

2 years ago

WILL GIVE BRAINLIEST!!! Given tan(theta) = 4/3 and pi < theta < (3pi)/2, find cos(2theta).

babymother [125]

Answer: $\cos 2 \theta = \dfrac{-7}{25}$

Step-by-step explanation:

Given: $\tan \theta = \dfrac{4}{3}$ and $\pi < \theta< \dfrac{3\pi }{2}$

To find: $\cos 2 \theta$

Now as we know

$\cos 2x = \dfrac{1- \tan ^2 x}{1+ \tan ^2 x}$

So we have

$\cos 2 \theta = \dfrac{1-(\dfrac{4}{3} )^2}{1+(\dfrac{4}{3} )^2} \\\\\Rightarrow \cos 2 \theta = \dfrac{1- \dfrac{16}{9} }{1+ \dfrac{16}{9} } = \dfrac{\dfrac{9-16}{9} }{\dfrac{9+16}{9}} = \dfrac{-7}{25}$

Therefore d. is the correct option

Hence , $\cos 2 \theta = \dfrac{-7}{25}$

3 0

3 years ago

Read 2 more answers

Simplify the expression below.

natita [175]

Answer:

3m - 8

Step-by-step explanation:

Step by Step:

Equation= 6m³ - 16m² + 15m - 40/ 2m² + 5

Factor out 2m² from 6m³ - 16m²:

Factor out 5 from expression:

2m²(3m - 8) + 5(3m - 8)/2m² + 5

Factor out 3m - 8:

(3m - 8)(2m² + 5)/2m² + 5

Rude the fraction with 2m² + 5:

3m - 8 is the answer

I hope this helped!

3 0

3 years ago

Write each phrase or sentence as an algebraic expression or equation. DO NOT use a calculator. Do not write an inequality.

Temka [501]

Step-by-step explanation:

F. X- 12= 7

E. x+ y =18

B. 3y

4 0

3 years ago

The length of a rectangle is 3 cm less than its width what are the dimensions of the rectangle if its area is 270 cm²

kupik [55]

Given:

The length of a rectangle is 3 cm less than its width.

The area of the rectangle is 270 cm².

To find:

The dimensions of the rectangle.

Solution:

Let x be the width of the rectangle. Then,

$\text{Length}=x-3$

Area of a rectangle is:

$\text{Area}=\text{Length}\times \text{width}$

$270=(x-3)(x)$

$270=x^2-3x$

$0=x^2-3x-270$

Splitting the middle term, we get

$x^2-18x+15x-270=0$

$x(x-18)+15(x-18)=0$

$(x-18)(x+15)=0$

$x=18,-15$

Width of the rectangle cannot be negative. So, the only value of x is 18.

$Width=18$

$Length=18-3$

$Length=15$

Therefore, the length of the rectangle is 15 cm and the width of the rectangle is 18 cm.

7 0

2 years ago