A number that is 4 less than 2 is -2
Put the numbers in the data set in order from smallest to largest:
44, 45, 45, 47, 49, 50, 50, 51, 55, 55, 55, 56
The smallest number is 44, the largest is 56, so the outside lines need to be above those numbers.
Both A and B have that.
Now find the median ( the average of the middle two numbers)
The middle two numbers from the list are 50 and 50 so the median would be (50 +50) /2 = 100/2 = 50
The middle line inside the rectangle needs to be above 50.
This makes the answer A.
Answer:
When we have a function f(x), the average rate of change in the interval (a, b) is:

In this case, we have the function:
f(x) = (x + 3)^2 - 2
(but we do not have the interval, and I couldn't find the complete question online)
So if for example, we have the interval (2, 4)
The average rate of change will be:

If instead, we want the rate of change in a differential dx around the value x, we need to differentiate the function (this is way more complex, so I will define some rules first).
Such that the rate of change, in this case, will be:
f'(x) = df/dx
For a function like:
g(x) = x^n + c
g'(x) = n*x^(n - 1)
And for:
h(x) = k( g(x))
h'(x) = k'(g(x))*g'(x)
So here we can write our function as:
f(x) = k(g(x)) = (x + 3)^2 - 2
where:
g(x) = x + 3
k(x) = x^2 - 2
Then:
f'(x) = 2*(x + 3)*1 = 2*x + 6
That is the rate of change as a function of x (but is not an "average" rate of change)
Answer:
2π
Step-by-step explanation:
This is a little something you have to memorize, but you could derive it from the equation pb = 2π. In the parent function, the b value is 1, so the period, p, is equal to 2π/1 or just 2π.
1 = 144
2 = 144
3 = 36
4 = 90
5 = 144
6 = 36
7 = 144
8 = 90