The line has a positive slope. Let's look at all the slopes:
1) -3
2) -3
3) 3
4)3
Which ones are positive? That's right, 3 and 4. We don't know which equation would be the equation of the line. That's where the other information comes in.
The line intersects the y-axis at at a point that has a negative y-coordinate. Lets write the last two equations in slope-intercept form.
1) y = -3/2x - 5/2
2) y = -3/2x + 5/2
We have to graph both of the lines now. The graphs are at the very bottom. Take a look at them. In the first one, the y-intercept is a negative and in the second one, the y-intercept is positive.
The third one AKA 3x + 2y = -5 is the equation of the line. I hope this helps! Let me know if I got it wrong or if you need any more help.
120
OA = OB
angle OAN = 90 degrees, so OAB and OBA is both 30 degrees.
The problem ask to calculate the slope of the line tangent to a circle O at point A if the radius of the circle is 2.5. So based on the problem the tangent line formed a right angle so it means that the slope is also 2.5 and the answer is letter B. 2.5
Answer:
Answer:
4
Step-by-step explanation:
If you read it carefully then you'll get it :)
Step-by-step explanation:
The question is not properly structured but we can as well find the sum of 5/7 and 10 as shown;

Hence the expression written in equivalent form of common denominator is 
The sum is 