Answer:
y=(x+7)2(2x+1)(x−4)
y=2x4+21x3−4x2−399x−196
Step-by-step explanation:
Given: We have the given figure through which we can see
LK=16,
KJ=10,
LM=24,
MN=15
To Find: Whether KM || JN and the reasoning behind it.
Solution: Yes, KM || JN because 
Explanation:
For this solution, we use the concept of Similar Triangles.
Now, KM || JN if ΔLKM ~ ΔLJN (i.e., if ΔLKM is similar to ΔLJN).
Now, ∠MLK=∠NLJ
To prove similarity of the two triangles, we have to show that the sides are proportional. In other words, LK:KJ = LM:LN

which is true as both sides simplify to 
Thus, we see that ΔLKM ~ ΔLJN (i.e., if ΔLKM is similar to ΔLJN).
Therefore, KM || JN.
To come to the reasoning, notice that

In other words, 
Answer:
∠A1 = 27.4°, ∠A2 = 56.6°, ∠C1 =104.6°, ∠C2=75.4°, a1 = 79.9 and a2 = 144.9
Step-by-step explanation:
From Sine rule

∴ b / sinB = c / sinC
From the question,
b = 129, c = 168 and ∠B = 48°
∴ 129 / sin48° = 168 / sinC
Then, sinC = (168×sin48)/129
sinC = 0.9678
C = sin⁻¹(0.9678)
C = 75.42
∠C2=75.4°
and
∴∠C1 = 180° - 75.4°
∠C1 =104.6°
For ∠A
∠A1 = 180° - (104.6°+48°) [sum of angles in a triangle]
∠A1 = 27.4°
and
∠A2 = 180° - (75.4° + 48°)
∠A2 = 180° - (123.4°)
∠A2 = 56.6°
For side a
a1/sinA1 = b/sinB
a1/ sin27.4° = 129/sin48
a1 = (129×sin27.4°)/sin48
a1 = 79.8845
a1 = 79.9
and
a2/sinA2 = b / sinB
a2/ sin56.6° = 129/sin48
a2 = (129×sin56.6°)/sin48
a2 = 144.9184
a2 = 144.9
Hence,
∠A1 = 27.4°, ∠A2 = 56.6°, ∠C1 =104.6°, ∠C2=75.4°, a1 = 79.9 and a2 = 144.9
Answer: 176m^2
Step-by-step explanation:
The smaller rectangle is taking up space among the larger one. So in order to find the area of this shaded region, you need to subtract that smaller one from the larger one.
12 x 15 = 180
1 x 4 = 4
180 - 4 = 176m^2