Since it's a sample size, we use x, as the mean and s= standard deviation
_
Given: x =27, s = 2 and total sample = 32.
Probability that a recruit is at least 31 years old?
Let's calculate the Z score :
_
X - x 31 - 27
Z = ----------- → Z = -------- → Z = 2 (now look up in the Z score table,
s 2
Area (Z=2) =0.9772 , but Z ≥ 2 (at least) , then :
Area (Z≥2) = Area (Z≤ - 2) = 0.0228
P(≥31)= 0.0228
Answer:
-2
Step-by-step explanation:
Answer:
(2x + 1)(3x + 2)
Step-by-step explanation:
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 6 × 2 = 12 and sum = 7
The factors are + 3 and + 4
Use these factors to split the x- term
= 6x² + 3x + 4x + 2 ( factor the first/second and third/fourth terms )
= 3x(2x + 1) + 2(2x + 1) ← factor out (2x + 1) from each term
= (2x + 1)(3x + 2) ← in factored form
Answer:
27 men had a pulse rate between 56 & 100.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 36
Five number summary:
Lowest value: 56
Lower Quartile: 71
Median: 80
Upper Quartile: 100
Highest value: 140
We have to find the number of men that had a pulse rate between 56 & 100.
56 is the lowest value of data and 100 is the third quartile of data.
Now, the third quartile give 75 percentile of data, thus, 75% of data lies between lowest value and the third quartile.
Thus, 75% of men have a pulse rate between 56 & 100.
Number of men that had a pulse rate between 56 & 100 =
Thus, 27 men had a pulse rate between 56 & 100.
Start with 1 + (5 + x) + 4
Combine like terms: 10 + x
The answer is 10 + x
