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Evgesh-ka [11]
3 years ago
10

Can someone help me I'm so confused

Mathematics
2 answers:
pishuonlain [190]3 years ago
8 0
It's be because a coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression
nikklg [1K]3 years ago
4 0
A is the correct answer. A coefficient is just a number that appears in front of a variable. Please note that a number that doesn't have a variable behind it is still a coefficient since there is technically a variable behind it with a power of 0. 
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In the polynomial function below, what is the leading coefficient?
Andrei [34K]

Answer:

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Step-by-step explanation:

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5 0
2 years ago
The area of a rectangle is 45 cm2. Two squares are constructed such that two adjacent sides of the rectangle are each also the s
Zielflug [23.3K]

Answer:

The lengths of sides of squares are 5 cm and 9 cm.

Step-by-step explanation:

Let the sides of rectangle be x and y .

Area of rectangle = Length × Breadth

Given : Area of rectangle = 45 cm².

⇒ x × y  = 45  

⇒ x=\frac{45}{y}  ........(1)

Two squares are constructed such that two adjacent sides of the rectangle

so squares have side x and y .

Area of square = side × side

Area of square with side x = x²

Area of square with side y = y²

Also, The combined area of the two squares is 106 cm².

⇒ x² + y² = 106

From (1) put value of x , we get,

(\frac{45}{y})^2+y^2=106

Solving for y ,

(\frac{45}{y})^2+y^2=106  

2025+y^4=106y^2  

y^4-106y^2+2025=0  

y^4-81y^2-25y^2+2025=0  

y^2(y^2-81)-25(y^2-81)=0  

(y^2-25)(y^2-81)=0

y^2-81=0 or y^2-25=0    

on solving we get y = 5 and y = 9

Also, x can be find by putting in (1),

⇒ x=\frac{45}{5}=9 and ⇒ x=\frac{45}{9}=5  

⇒ x = 9 and x = 5

Thus, lengths of sides of squares are 5 cm and 9 cm.

6 0
3 years ago
Read 2 more answers
Select the correct name for the following line.
klio [65]
It's the first choice
4 0
2 years ago
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What is the approximate volume of a cone with a height of 12 in. and radius of 9 in.?
Arisa [49]
Volume of the cone = 1/3π r^2 h
So, we are given that r = 9 and h = 12
plugging in all the known values 
1/3 * (3.14) * 9 * 9 * 12
= 1017.36 cm³
or
≈1017.4 cm³
8 0
3 years ago
V= <img src="https://tex.z-dn.net/?f=v%3D%20%5Cpi%20r%20%5E%7B2%7D%20h%20%20for%20%20%202%20" id="TexFormula1" title="v= \pi r ^
swat32
V=\pi r^2h \\\\ r^2=\frac{V}{\pi h} \\\\ \boxed{r=\sqrt\frac{V}{\pi h}}
3 0
3 years ago
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