Which point is an x-interceptof the quadratic function f(x)=x-4)(x+2)
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Let that be
Two vertical asymptotes at -1 and 0
If we simply
- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
- 3x²+9x
Find zeros
- 3x²+9x=0
- 3x(x+3)=0
- x=0,-3
Horizontal asymptote
- 3x²/x²
- 3
So our equation is
Graph attached
