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Olin [163]
3 years ago
9

Describe the end behavior of a 14th degree polynomial with a positive leading coefficient.

Mathematics
1 answer:
DiKsa [7]3 years ago
8 0

<u><em>Answer:</em></u>

1)

f(x)→ ∞ when x→∞ or x→ -∞.

2)

when  x→ ∞ then f(x)→ -∞

        and when x→ -∞ then f(x)→ ∞

<u><em>Step-by-step explanation:</em></u>

<em>" The </em><em>end behavior</em><em> of a polynomial function is the behavior of the graph of as approaches positive infinity or negative infinity. The degree and the leading coefficient of a polynomial function determine the end behavior of the graph "</em>

1)

a 14th degree polynomial with a positive leading coefficient.

Let f(x) be the polynomial function.

Since the degree is an even number and also the leading coefficient is positive so when we put negative or positive infinity to the function i.e. we put x→∞ or x→ -∞ ; it will always lead the function to positive infinity

i.e. f(x)→ ∞ when x→∞ or x→ -∞.

2)

a 9th degree polynomial with a negative leading coefficient.

As the degree of the polynomial is odd and also the leading coefficient is negative.

Hence when x→ ∞ then f(x)→ -∞ since the odd power of x will take it to positive infinity but the negative sign of the leading coefficient will take it to negative infinity.

When x→ -∞ then f(x)→ ∞; since the odd power of x will take it to negative infinity but the negative sign of the leading coefficient will take it to positive infinity.

Hence, when  x→ ∞ then f(x)→ -∞

        and when x→ -∞ then f(x)→ ∞



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Which expression is equivalent to (7x-5) - (3x - 2)
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4 years ago
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Alexandra [31]

Answer:

Her average was 87.35% on this course.

Step-by-step explanation:

In order to determine Marissa's average we need to take the average she has on each of the cattegories and find how much that relates to the weight of the  cattegory on the final grade. We have:

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Quizzes counts for 20% of the grade and she has a 93% average on that. So we have:

Quizzes = weigth*(Marissa's average)

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B is the y-intercept. In this equation the y intercept is 40. A y- intercept is where the graph crosses the y axis so at the point (0,40) the graph crosses the y axis.

M is the slope which is rise over run so if the slope was 10 (which it is) 10 is equivalent to 10/1 so you move up 10 units for every 1 unit you move across.

So to graph this equation, you would draw your first point at (0,40). For your next point, you would move right one unit, and up 10 units. Draw a point there which would be (1, 50). Hopefully you understand. For going left from the y intercept point, you would move left 1 and down 10.

Actual graph above.

Hope this helps C:

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