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babunello [35]
3 years ago
14

Parallelogram efgh has sides of length 20 inches and 14 inches as shown. Its acute angle measures 62 degrees. Find the area of e

fgh to the nearest square inch
Mathematics
1 answer:
Solnce55 [7]3 years ago
4 0

Answer:

The area of the parallelogram is 247 inches^2 to the nearest square inch

Step-by-step explanation:

This question asks us to calculate the area of a parallelogram given the sides and an acute angle.

Please check attachment for diagrammatic representation of the said parallelogram.

Mathematically, the area of the parallelogram can be calculated using the formula;

A = ab sin θ

where a and b refers to the length of the two sides and θ being the acute angle

Substituting these values, we have

A = 20 * 14 * sin 62

A = 280 sin 62 = 247.23 which is 247 inches^2 to the nearest square inch

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Answer

He packed 3 more


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3 years ago
Exercice 2: Un remorqueur tire un bateau à la vitesse de 10 noeuds. La tension du câble est de 2500N, Le câble est parallèle à l
Elza [17]

Répondre:

1 285 watts

Explication étape par étape:

La puissance est exprimée selon la formule;

power = travail effectué / temps

Puissance = Force * (distance / temps)

Depuis Vitesse = distance / temps

Puissance = Force * vitesse

Donné

Force = 2500N

Vitesse (en m / s) = 0,514 m / s

Obligatoire

Puissance

Remplacez la formule donnée;

Puissance = 2500 * 0,514

Puissance = 1,285Watts

Par conséquent, la puissance correspondante requise est de 1285 watts

5 0
3 years ago
(x,-4) and (2,8); m=_3
DerKrebs [107]

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3 years ago
Find the Surface Area of Rectangular Prism
Leviafan [203]

Answer:

4 X 3 = 12 , 12 X 2 = 24

5 X 4 = 20, 20 X 2 = 40

3 X 5 = 15, 15 X 2 = 30

30 + 40 + 24 = 94 cm squared

6 0
3 years ago
HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
ivolga24 [154]

<u>Answer:</u>

<h2>A = 15 u²</h2>

<u>Explanation:</u>

according to the coordinates the triangles is right at the pair (2, -3)

the area of the triangle = height × base × 1/2

the <u>height</u> is the line passing through the pairs (-1, 6) and (2, -3)

h² = (2-(-1))²+(-3-6)²

h² = 3² + (-9)²

h² = 9 + 81

h² = 90

h = √90

the <u>base</u> is the line passing through the pairs (5, -2) and (2, -3)

b² = (2-5)²+(-3-(-2))²

b² = 3² + (-3+2)²

b² = 9 + 1

b² = 10

b = √10

A = h×b×1/2

A = √90×√10×1/2

A = √900×1/2

A = 30×1/2

A = 15 u²

5 0
3 years ago
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