Answer: slope is 1 1/3
Y2-y1
Over
X2-x1
9-1
8-2
8/6 is 1 1/3
Step-by-step explanation:
Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Answer:
no, not proportional
Step-by-step explanation:
set up a proportion and see if cross-products are equal:
8/3 = 14/6
cross-multiply:
(8)(6) ≠ (14)(3)
48 ≠ 42
1. the last one
2.the first one hope this helps.