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julsineya [31]
4 years ago
12

4. Haniya bought 4 polka dot pencils that eachcost 70. How much money did Haniya spend?​

Mathematics
2 answers:
Maurinko [17]4 years ago
4 0
70 x 4 = 280

the answer is 280
olga2289 [7]4 years ago
3 0
Either 280 dollars or 2.80 depends on if you meant 70 cents
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Which statement is true about the graphs of the two lines and ? y= -8x -5/4 and y = 1/8x + 4/5
Ronch [10]
Y = -8x - 5/4......slope here is -8 or -8/1
y = 1/8x + 4/5...slope here is 1/8

what u have here are negative reciprocal slopes....negative reciprocal of a number can be found by flipping the number and changing the sign. So the negative reciprocal of -8/1 is 1/8 (see how I flipped the number and changed the sign)...and when u have negative reciprocal slopes, this means that ur lines are perpendicular.
7 0
3 years ago
true or false in order to find the lateral surface area you must know the area of the base of the prism​
natima [27]

Answer:

True sorry if I’m wrong

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the minimum value of C = 7x + 8y, given the constraints: 2x + y ≥ 8, x + y ≥ 6, x ≥ 0, y ≥ 0. A. 32 B. 42 C. 46 D. 64
marshall27 [118]

Answer: The minimum value of C is 46.

Step-by-step explanation:

Since, Here, We have to find out Min C = 7x+8y

Given the constraints are 2x+y\geq 8 -------(1)

x+y \geq 6   ------------- (2)

x \geq 0, y \geq 0  -------- (3)

Since, For equation 1) x-intercept, (4, 0) and y-intercept (0,8)

And, 2\times 0+0\geq 8⇒0\geq 8 ( false)

Therefore the area of line 1) does not contain the origin.

For equation 2) x-intercept, (6, 0) and y-intercept (0,6)

And, 0+0\geq 6⇒0\geq 6 ( false)

Therefore the area of line 2) does not contain the origin.

Thus after plotting the constraints 1) 2) and 3) we get Open Shaded feasible region AEB ( Shown in below graph)

At A≡(0,8) , C= 64

At E≡(2,4),  C= 46

At B≡(6,0),  C= 42

Thus at B, C is minimum, And its minimum value = 42


5 0
3 years ago
Read 2 more answers
Find the distance between the points.<br> (0,4) and (-3,4)<br> The distance is
Inessa [10]
<h3>Answer:  3 units</h3>

=============================================================

Explanation:

The y coordinates are identical, so we just need to focus on the x coordinates.

Going from 0 to -3 is a distance of 3 units. Drawing out a number line might help.

Or we could apply subtraction and absolute value

|x1-x2| = |0-(-3)| = |0+3| = |3| = 3

which is the same as

|x2-x1| = |-3-0| = |-3| = 3

The absolute value is to ensure the result is never negative. Distance is never negative.

Side note: if the y coordinates weren't the same, then we'd have to use either the pythagorean theorem or the distance formula.

4 0
3 years ago
Find the point of intersection (if any) of the following pairs of lines: a) x – 2y +1=0 2x + 3y – 7 = 0 b) x-2y+11=0 -x+2y-13 =
pychu [463]

Answer:

a) (11/7, 9/7)

b) There's no point of intersection

Step-by-step explanation:

a) x - 2y + 1 = 0

2x + 3y - 7 = 0

To find the point of intersection, we need to solve the system of equations  and the result will be the point of intersection (x,y)

x-2y+1=0\\x= 2y-1

Now we substitute x in the second equation:

2x+3y-7=0\\2(2y-1)+3y-7=0\\4y-2+3y-7=0\\7y-9=0\\y=9/7

Now we substitute y in our first equation.

x-2y+1=0\\x-2(9/7)+1=0\\x-18/7+1=0\\x=18/7-1\\x=11/7.

The point of intersection is (11/7, 9/7)

b) x -2y +11 =0

-x + 2y - 13 =0

We are going to follow the same procedure:

x-2y+11=0\\x=2y-11

-(2y-11)+2y-13=0\\-2y+11+2y-13=0\\0y=2\\0=2

Since this system of equations doesn't have a solution, the system has no point of intersection.

5 0
3 years ago
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