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attashe74 [19]
2 years ago
15

A spinner and 2 cards are shown below:

Mathematics
2 answers:
Murljashka [212]2 years ago
8 0
P(red AND green card) = P(red) * P(green card)

P(red) = 1/7 (i.e. one color out of total of seven)
P(green card) = 1/2 (i.e. one card out of two)

P(red AND green card) = 1/7 * 1/2 = 1/14
OLEGan [10]2 years ago
7 0
<h3><u>Answer:</u></h3>

Hence, probability that the spinner stops at red and a green card is selected is:

1 over 14

<h3><u>Step-by-step explanation:</u></h3>

It is given that a spinner and two cards are selected.

A spinner has 7 colors in it:

Green,Red,Orange, Violet, Pink, Yellow, and Blue are marked on it.

Two cards are shown on the right side. The colors Purple and Green are marked on them.

Now we are asked to find the probability that the spinner stops at red and a green card is selected.

Let A  denotes the event that the arrow stops at red.

and B denote the event that a green card is selected.

Now, we have to find:

P(A∩B)

Where P denotes the probability of an event.

As we know that event A and event B are independent.

Hence,

P(A∩B)=P(A)×P(B)

Now,

P(A)=1/7

( Since we have 7 choices out of which only one sector has red color)

Similarly,

P(B)=1/2

( since we have just two cards and one card is green).

Hence,

P(A∩B)=(1/7)×(1/2)=1/14

Hence, probability that the spinner stops at red and a green card is selected is:

1 over 14

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Answer: False

Step-by-step explanation:

There is no such deduction when a participation's questions are not answered correctly the first time. Whatever answer is given is part of the learning curve and ensures that the activity can be improved upon.

Had there been a small point deduction then there would be no opportunity to learn because there would be too much fear associated with the wrong answer.

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Step-by-step explanation:


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The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

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