Question

A spinner and 2 cards are shown below:

Answer 1

P(red AND green card) = P(red) * P(green card)

P(red) = 1/7 (i.e. one color out of total of seven)
P(green card) = 1/2 (i.e. one card out of two)

P(red AND green card) = 1/7 * 1/2 = 1/14

Answer 2

Answer:

Hence, probability that the spinner stops at red and a green card is selected is:

1 over 14

Step-by-step explanation:

It is given that a spinner and two cards are selected.

A spinner has 7 colors in it:

Green,Red,Orange, Violet, Pink, Yellow, and Blue are marked on it.

Two cards are shown on the right side. The colors Purple and Green are marked on them.

Now we are asked to find the probability that the spinner stops at red and a green card is selected.

Let A  denotes the event that the arrow stops at red.

and B denote the event that a green card is selected.

Now, we have to find:

P(A∩B)

Where P denotes the probability of an event.

As we know that event A and event B are independent.

Hence,

P(A∩B)=P(A)×P(B)

Now,

P(A)=1/7

( Since we have 7 choices out of which only one sector has red color)

Similarly,

P(B)=1/2

( since we have just two cards and one card is green).

Hence,

P(A∩B)=(1/7)×(1/2)=1/14

Hence, probability that the spinner stops at red and a green card is selected is:

1 over 14