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3 years ago

Gathering Ideas

Business

1 answer:

Vsevolod [243]3 years ago

7 0

Answer:

To improve the group's brainstorming, Jeanne should .

A. use flip-charts and classify ideas

You chose your favorite doodle, and put it on a reusable cup. This is an example of:

A. Crowd-storming

Explanation:

It is because the group discussion was efficient as lots of ideas come out, but due to lots of ideas, few ideas were remembered. Hence, Jeanne should use flip charts and write each and everything about that particular idea in detail, so at last, she could make a proper comparison of the ideas and pick the most feasible idea.

It is because the company took the ideas from the crowd, which represents the bulk of ideas and to makes a choice for the doodle to put it on the cup. Hence, the company stormed the ideas of the crowd and used it in its task. It is considered as an example of Crowd-storming.

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Karen runs a print shop that makes posters for large companies. it is a very competitive business. the market price is currently

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She has fixed costs of $250. Her variable costs are $1,000 for the first thousand posters, Her variable costs are $800 for the second thousand Her variable costs are $750 for each additional thousand posters. To calculate Average fixed cost that is AFC per poster we need two factors: Total fixed cost = 250 and Number of poster = 1000 So now AFC will be (250/1000) that is 0.25.

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3 years ago

", describe the ways in which Volkswagen did not fulfill the requirements of effective corporate governance. In one or two parag

Zielflug [23.3K]

Answer: Volkswagen Emission scandal

Explanation: The Supervisory Board should be “responsible for monitoring the Management and approving important corporate decisions , however “investors and governance experts say the emissions scandal shows that it lacks the independence and authority to do this” .

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Many officials at Volkswagen were unaware of any wrongdoing, although this suggests the company can be salvaged and there are people at the top that can help turn this back around. It does also highlight the need for serious improvement in terms of the firm's internal controls. For issues on a scale as large as this, there should be a sound whistle blowing system in place to alert the correct people of such instances, so action can be taken before any issue further escalates

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4 years ago

On September 1, Horton purchased $13,300 of inventory items on credit with the terms 1/15, net 30, FOB destination. Freight char

sashaice [31]

Answer:

C) $13,167

Explanation:

Since the sales was made FOB destination, the freight charges were included in the invoice, so the total purchase was $13,300.

Horton uses the net method of accounting for purchase discounts, so it will always record the inventory purchases with the applicable discount whether they received them or not.

$13,300 x 99% = $13,167

Since Horton was unable to pay in time, the $133 discount is recorded as a discount lost (expense account).

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3 years ago

Show that the set of vectors {(−4,1,3),(5,1,6),(6,0,2)} does not span R 3 , but that it does span the subspace of R 3 consisting

Alika [10]

Answer:

The vectors does not span R3 and only span a subspace of R3 which satisfies x+13y-3z=0

Explanation:

The vectors are given as

$v_1=\left[\begin{array}{c}-4&1&3\end{array}\right] \\v_2=\left[\begin{array}{c}-5&1&6\end{array}\right] \\v_3=\left[\begin{array}{c}6&0&2\end{array}\right]$

Now if the vectors would span the $R^3$ , the rank of the consolidated matrix will be 3 if it is not 3 this indicates that the vectors does not span the $R^3$ .

So the matrix is given as

$M=\left[\begin{array}{ccc}v_1&v_2&v_3\end{array}\right] \\M=\left[\begin{array}{ccc}-4&5&6\\1&1&0\\3&6&2\end{array}\right]\\$

In order to calculate the rank, the matrix is reduced to the Row Echelon form as

$\approx \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{9}{4}&\frac{3}{2}\\ 3&6&2\end{array}\right] R_2 \rightarrow R_2+\frac{R_1}{4}$

$\approx \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{9}{4}&\frac{3}{2}\\ 0&\frac{39}{4}&\frac{13}{2}\end{array}\right] R_3 \rightarrow R_3+\frac{3R_1}{4}\\$

$\approx \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{39}{4}&\frac{13}{2\\ 0&\frac{9}{4}&\frac{3}{2}}\end{array}\right] R_2\:\leftrightarrow \:R_3$

$\approx \left[\begin{array}{ccc}-4&5&6\\ 0&\frac{39}{4}&\frac{13}{2}\\ 0&0&0\end{array}\right] R_3 \rightarrow R_3-\frac{3R_2}{13}\\$

As the Rank is given as number of non-zero rows in the Row echelon form which are 2 so the rank is 2.

Thus this indicates that the vectors does not span $R^3$

Now for any vector the corresponding equation is formulated by using the combined matrix which is given as for any arbitrary vector and the coordinate as

$v=\left[\begin{array}{c}x&y&z\end{array}\right]$

$c=\left[\begin{array}{c}c_1&c_2&c_3\end{array}\right]$

$Mc=v$

$\left[\begin{array}{ccc}-4&5&6\\1&1&0\\3&6&2\end{array}\right]\left[\begin{array}{c}c_1&c_2&c_3\end{array}\right]=\left[\begin{array}{c}x&y&z\end{array}\right]$

$M=\left[\begin{array}{ccccc}v_1&v_2&v_3& | &v\end{array}\right] \\M=\left[\begin{array}{ccccc}-4&5&6&|&x\\1&1&0&|&y\\3&6&2&|&z\end{array}\right]\\$

Now converting the combined matrix as

$\approx \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{9}{4}&\frac{3}{2}&|&\frac{4y+x}{4}\\ 3&6&2&|&z\end{array}\right] R_2 \rightarrow R_2+\frac{R_1}{4}\\$

$\approx \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{9}{4}&\frac{3}{2}&|&\frac{4y+x}{4}\\ 0&\frac{39}{4}&\frac{13}{2}&|&\frac{4z+3x}{4}\end{array}\right] R_3 \rightarrow R_3+\frac{3R_1}{4}\\$

$\approx \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{39}{4}&\frac{13}{2}&|&\frac{4z+3x}{4}\\ 0&\frac{9}{4}&\frac{3}{2}&|&\frac{4y+x}{4}\end{array}\right] R_3 \leftrightarrow R_2\\$

$\approx \left[\begin{array}{ccccc}-4&5&6&|&x\\ 0&\frac{39}{4}&\frac{13}{2}&|&\frac{4z+3x}{4}\\ 0&0&0&|&\frac{13y+x-3z}{13}\end{array}\right] R_3 \rightarrow R_3-\frac{3R_2}{13}\\$

From this it is seen that whatever the values of the coordinates does not effect the value of the plane with equation as

$\frac{13y+x-3z}{13}=0\\or\\13y+x-3z=0\\$

So it is verified that the subspace of R3 such that it satisfies x+13y-3z=0 consists of all vectors.

6 0

3 years ago

The free cash flow to the firm is reported as $205 million. The interest expense to the firm is $22 million. If the tax rate is

Natasha_Volkova [10]

Answer:

$2,445

Explanation:.

Calculation for the approximate market value of the firm

First step is to calculate the FCFE

FCFE = 205 - 22(1 - .35) + 25

FCFE=205-22(.65) + 25

FCFE=205-14.3+ 25

FCFE = 215.70

Second Step is to calculate the Market Value

Market Value = (215.70×1.02)/(.11 - .02)

Market Value=220.014/0.09

Market Value= $2,445

Therefore the approximate market value of the firm will be $2,445

4 0

3 years ago