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elena-14-01-66 [18.8K]
4 years ago
10

Converting Units of Rates

Mathematics
2 answers:
vovangra [49]4 years ago
6 0

Answer:

Step 2 : 1 mile 5'280 feet Is the answer

to Simplify it for you And step 3 : 60 minutes 1 hour

||||| Step Four is Intelligible i don't know that one yet

Step-by-step explanation:

I just got it right

ollegr [7]4 years ago
4 0

Here is the answer:  

Converting Units of Rates

Try it

Sam ran 63,756 feet in 70 minutes. What is Sam's rate in

miles per hour? 10.34

Step 1: What is Sam's rate as stated?

63,756 feet

63,756 ft

70 min

70 minutes

Step 2: What factor is used to convert feet per minute into

miles per minute?

5.280 feet

1 foot

1 mile

1 minute

Check

Hope this helps.

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Answer:

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Step-by-step explanation:

<u>The complete question is</u>: In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones were in use by the household.​ (No two respondents were from the same​ household.) Among the​ respondents, 215 answered​ "none", 280 said​ "one", 362 said​ "two", 149 said​ "three," and 140 responded with four or more. A survey respondent is selected at random. Find the probability that​ his/her household has four or more cell phones in use. Is it unlikely for a household to have four or more cell phones in​ use? Consider an event to be unlikely if its probability is less than or equal to 0.05.

We are given that among the​ respondents, 215 answered​ "none", 280 said​ "one", 362 said​ "two", 149 said​ "three," and 140 responded with four or more.

A survey respondent is selected at random.

As we know that the probability of any event is calculated as;

                Probability = \frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}

Here, we have to find the probability that​ his/her household has four or more cell phones in use;

Number of respondent having four or more cell phones in use = 140

Total number of respondents asked = 215 + 280 + 362 + 149 + 140 = 1146

<u>So, the required probability</u> = \frac{140}{1146}

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No, it is not unlikely for a household to have four or more cell phones in​ use because the probability is not less than or equal to 0.05 but in actual it is greater than 0.05.

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