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frosja888 [35]
3 years ago
8

A rectangular rug has a perimeter of 20 feet. The length of the rug is 6 feet. What is the width of the rug in inches?

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0

Answer:

48 in

Step-by-step explanation:

The length of the rug is 6 feet. We know this must account for 2 sides of the rug, so let's multiply 6 by 2.

6 × 2 = 12

Now subtract 12 from 20.

20 - 12 = 8

Now divide 8 by 2 to find the measurement of the remaining two sides.

8 ÷ 2 = 4.

The width of the rug is 4 feet. The question wants to find the width in inches, however. So multiply 4 by 12 because there are 12 inches in each foot.

4 × 12 = 48

The width of the rug is 48 inches.

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Step-by-step explanation:

The centroid theorem states that the centroid of a triangle is 2/3 of the distance from a vertex to the midpoint of the opposite side.

That means that BH is 2/3 of the length BF.

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Viktor [21]

Answer:

Second choice:

x=2t

y=4t^2+4t-3

Fifth choice:

x=t+1

y=t^2+4t

Step-by-step explanation:

Let's look at choice 1.

x=t+1

y=t^2+2t

I'm going to subtract 1 on both sides for the first equation giving me x-1=t. I will replace the t in the second equation with this substitution from equation 1.

y=(x-1)^2+2(x-1)

Expand using the distributive property and the identity (u+v)^2=u^2+2uv+v^2:

y=(x^2-2x+1)+(2x-2)

y=x^2+(-2x+2x)+(1-2)

y=x^2+0+-1

y=x^2

So this not the desired result.

Let's look at choice 2.

x=2t

y=4t^2+4t-3

Solve the first equation for t by dividing both sides by 2:

t=\frac{x}{2}.

Let's plug this into equation 2:

y=4(\frac{x}{2})^2+4(\frac{x}{2})-3

y=4(\frac{x^2}{4})+2x-3

y=x^2+2x-3

This is the desired result.

Choice 3:

x=t-3

y=t^2+2t

Solve the first equation for t by adding 3 on both sides:

x+3=t.

Plug into second equation:

y=(x+3)^2+2(x+3)

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

y=(x^2+6x+9)+(2x+6)

y=(x^2)+(6x+2x)+(9+6)

y=x^2+8x+15

Not the desired result.

Choice 4:

x=t^2

y=2t-3

I'm going to solve the bottom equation for t since I don't want to deal with square roots.

Add 3 on both sides:

y+3=2t

Divide both sides by 2:

\frac{y+3}{2}=t

Plug into equation 1:

x=(\frac{y+3}{2})^2

This is not the desired result because the y variable will be squared now instead of the x variable.

Choice 5:

x=t+1

y=t^2+4t

Solve the first equation for t by subtracting 1 on both sides:

x-1=t.

Plug into equation 2:

y=(x-1)^2+4(x-1)

Distribute and use the binomial square identity used earlier:

y=(x^2-2x+1)+(4x-4)

y=(x^2)+(-2x+4x)+(1-4)

y=x^2+2x+-3

y=x^2+2x-3.

This is the desired result.

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3 years ago
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