Answer:
The slope of ladder is not within the safe range .
Step-by-step explanation:
Given as :
The height of the ladder up a wall = h = 2 meters
The distance of base of ladder from the wall = x = 0.4 meters
The estimated safety range of slope of ladder is between 6.3 and 9.5
Let The slope of the ladder = x
<u>According to question</u>
slope of the ladder = 
Or, x = 
Or, x = 5
So, The slope of the ladder = x = 5
Since The estimated range of slope between 6.3 and 9.5
And The calculate slope of ladder = 5
Hence, The slope of ladder is not within the safe range . Answer
let's firstly convert the mixed fractions to improper fractions and then get their difference.
![\stackrel{mixed}{8\frac{7}{8}}\implies \cfrac{8\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{71}{8}} ~\hfill \stackrel{mixed}{6\frac{3}{4}}\implies \cfrac{6\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{27}{4}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{71}{8}-\cfrac{27}{4}\implies \cfrac{1(71)~~ -~~2(27)}{\underset{\textit{using this LCD}}{8}}\implies \cfrac{71-54}{8}\implies \cfrac{17}{8}\implies 2\frac{1}{8}](https://tex.z-dn.net/?f=%5Cstackrel%7Bmixed%7D%7B8%5Cfrac%7B7%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B8%5Ccdot%208%2B7%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B71%7D%7B8%7D%7D%20~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B6%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B6%5Ccdot%204%2B3%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B27%7D%7B4%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B71%7D%7B8%7D-%5Ccfrac%7B27%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B1%2871%29~~%20-~~2%2827%29%7D%7B%5Cunderset%7B%5Ctextit%7Busing%20this%20LCD%7D%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B71-54%7D%7B8%7D%5Cimplies%20%5Ccfrac%7B17%7D%7B8%7D%5Cimplies%202%5Cfrac%7B1%7D%7B8%7D)
(5x + 3)(5x – 3)
(7x + 4)(7x + 4)
(x – 9)(x – 9)
(–3x – 6)(–3x + 6)
Answer:
This question answer is attached in the attachment,
Step-by-step explanation:
Answer:
7.81 u
Step-by-step explanation:
<u>Given :- </u>
- Two points (3,3) and (-2,-3) is given to us.
And we need to find out the distance between the two points . So , here we can use the distance formula to find out the distance. As,
D = √{(x2-x1)² + (y2-y1)²}
D =√[ (3+2)² +(-3-3)²]
D =√[ 5² +6²]
D =√[ 25 +36]
D = 61
D = 7.81
<h3>Hence the distance between the two points is 7.81 units .</h3>