Answer: 0) 0.22
1) 0.20
2) 0.12
3) 0.14
4) 0.28
5) 0.04
<u>Step-by-step explanation:</u>
The total frequency is 33+30+18+21+42+6 = 150. This means they ran the experiment 150 times. The probability (P) is calculated by the satisfactory number of outcomes (frequency) divided by the total number of experiments/outcomes (total frequency):
![\begin{array}{c|c||lc}\underline{x}&\underline{f}&\underline{f\div 150}&\underline{\text{P}}\\0&33&33\div 150=&0.22\\1&30&30\div150=&0.20\\2&18&18\div 150=&0.12\\3&21&21\div 150=&0.14\\4&42&42\div 150=&0.28\\5&6&6\div 150=&0.04\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7C%7Clc%7D%5Cunderline%7Bx%7D%26%5Cunderline%7Bf%7D%26%5Cunderline%7Bf%5Cdiv%20150%7D%26%5Cunderline%7B%5Ctext%7BP%7D%7D%5C%5C0%2633%2633%5Cdiv%20150%3D%260.22%5C%5C1%2630%2630%5Cdiv150%3D%260.20%5C%5C2%2618%2618%5Cdiv%20150%3D%260.12%5C%5C3%2621%2621%5Cdiv%20150%3D%260.14%5C%5C4%2642%2642%5Cdiv%20150%3D%260.28%5C%5C5%266%266%5Cdiv%20150%3D%260.04%5Cend%7Barray%7D%5Cright%5D)
Answer:
Since a Pythagorean triple is three positive integers a, b, and c such that (a^2)+(b^2)=(c^2), where a and b are the two legs, and c is the hypotenuse, first take the sum of the squares of the two legs and make an estimate. For example, 3, 4, and 5 is a Pythagorean triple since 9+16=25.
Answer:
≈ 58
Step-by-step explanation:
Estimation usually means you want an answer good to one or maybe two significant figures. That usually means you want to round the numbers involved to one or two significant figures.
Doing that here transforms the problem to 180/3 = 60, an answer with one significant figure.
You can improve the estimate a bit by recognizing that it is a little high (the numerator is higher than 175.32, but the denominator is the same). Since the numerator is high by about 5, the estimate is high by about 5/3 or a little less than 2. A closer estimate will be 60 - 2 = 58.
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The degree to which you refine the estimate will depend on the error requirements you have. Certainly an estimate of 60 is within 10% of the true value, so is "close enough" for many purposes.
