Answer:
vertical asymptote at x = 7
horizontal asymptote at y = 6
Step-by-step explanation:
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.
solve:
x
−
7
=
0
⇒
x
=
7 is the asymptote
Horizontal asymptotes occur as
lim
,f(x)→
c(a constant)
x
→
±
∞
divide terms on numerator/denominator by x
f
(
x
)
=
5/
x
+6=
5
/x
+
6
x/
x
−
7
/x 1
−
7/
x
as
x
±
∞
,
f
(
x
)
→
0
+6
1
−
0
⇒
y
=
6 is the asymptote
graph{((5)/(x-7))+6 [-20, 20, -10, 10]}
Answer:
The correct answer is: p - 8 ∧ restriction p ≠ -4
Step-by-step explanation:
(p² - 4 p - 32) / ( p + 4)
The existence of this rational algebraic expression is possible only if it is:
p + 4 ≠ 0 => Restriction is p ≠ -4
(p² - 4 p - 32) / ( p + 4) = (p² - 8 p + 4 p - 32) / (p + 4) =
= (p (p -8) + 4 (p -8)) / (p + 4)= (p - 8) (p + 4) / ( p +4) = p - 8
God with you!!!
Answer:
it increased 50%
Step-by-step explanation:
5 / 2.5 = 2
100 / 2 = 50%
0.25 or 1/4 as a fraction
