Answer:
14.69% probability that defect length is at most 20 mm
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
What is the probability that defect length is at most 20 mm
This is the pvalue of Z when X = 20. So
has a pvalue of 0.1469
14.69% probability that defect length is at most 20 mm
What huh? I don’t rly understand
I like that you left How you did it on there. When I was in school I did it the same way. I would assume you’re using is over of equals percent over 100. The problem however is that the above number is always the total which means it should be on the bottom.
X/72= 45/100. Similar to what you have written. Solve the proportion. 100x=72x45
100x= 3240
X = 32.4
Answer:
53.76
Step-by-step explanation:
B x W x H and divide by two is your answer.
In bank A, after one year this would be the amount in the bank:
<span>$7,000 x 1.04 = $7280. </span>
<span>He has gained %280 interest. This means you'd need $1000 interest from bank B. </span>
<span>$13,000 would go into bank B... </span>
<span>If Seth's interest rate was 8.69% you could calculate the interest as: </span>
<span>(13000 x 1.0869) - 13,000 = $1129.70 which is a little much (but who'd complain). </span>
<span>This means the interest is lower than this, if it was 7.69% you could just substitute it into the same equation to find that he would get $999.70 interest. This isn't exactly $1000 but it is the most accurate answer to the nearest $100 :) He would then get $1279.70 interest altogether.. just 30 cents short</span>
