Question

An ideal gas is at a pressure of 1.4 atm and has a volume of 3 L. If the gas is compressed to a volume of 1.0 L while its temperature is held constant, what is the resulting pressure to the nearest tenth of an atm?

Answer 1

Answer:

The resulting pressure is 4.2 atm. Since it's an ideal gas we use the ideal gas equation to calculate the final pressure.

Explanation:

p.v=n.R.T

This applies to both initial and final conditions of the gas, since the temperature is held constant:

$\frac{P_{1}.V_{1}}{n_{1}.R}=\frac{P_{2}.V_{2}}{n_{2}.R}$

And using this equation we find the value of pressure:

$\frac{1.4atm.3L}{1L}=p_{2}$