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Andrej [43]
3 years ago
10

Can someone solve this for me? Common factor first! Thank you.

Mathematics
2 answers:
USPshnik [31]3 years ago
5 0

Answer:

5 {(x - 4)}^{2}

Step-by-step explanation:

5 {x}^{2}  - 40x + 80 \\  =5( {x}^{2} - 8x + 16) \\  = 5 ( {x}^{2}   - 8x +  {4}^{2}  ) \\  = 5 {(x - 4)}^{2}

makkiz [27]3 years ago
3 0

Answer:

\boxed{\sf \ \ \ 5(x-4)^2 \ \ \ }

Step-by-step explanation:

hello

step 1 - divide by 5

5x^2-40x+80=5(x^2-8x+16)

step 2 - solving the square

(x-4)^2=x^2-8x+16

Finally, to answer the question

5x^2-40x+80=5(x-4)^2

hope this helps

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What are all the steps to solving a Quadratic Formula? (steps please)
nika2105 [10]

Compose the quadratic condition in standard shape, ax2 + bx + c = 0. Recognize the values of a, b, c. Write the Quadratic Equation. At that point substitute within the values of a, b, c. Simplify. Check the arrangements.

4 0
2 years ago
A bank sampled its customers to determine the proportion of customers who use their debit card at least once each month. A sampl
Zinaida [17]

Answer:

(0.084,0.396)

Step-by-step explanation:

The 99% confidence interval for the proportion of customers who use debit card monthly can be constructed as

p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }

p=\frac{x}{n}

p=\frac{12}{50}

p=0.24

q=1-p=1-0.24=0.76

\frac{\alpha }{2} =\frac{\0.01 }{2}=0.005

p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }

0.24-z_{0.005} \sqrt{\frac{0.24*0.76}{50} }

0.24-2.58(0.0604)

0.24-0.155832

By rounding to three decimal places we get,

0.084

The 99% confidence interval for the proportion of customers who use debit card monthly is (0.084,0.396).

3 0
3 years ago
What is the distance from point (-5,-4) to (9,2)?
Natasha2012 [34]

Answer:

radical 232

Step-by-step explanation:

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196+36= 232

radical 232

8 0
3 years ago
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Question 4 of 40
UkoKoshka [18]

Answer:

A. The ability to do something well without wasted time or effort.

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2 years ago
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
3 years ago
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