Area as a function of width, w is:
a(w)=(w-25)^2+625
for maximum area, the width will be:
a'(w)=2(w-25)+0=0
solving for w we egt
2w-50=0
2w=50
w=25 m
given that the perimeter is 100, the length will be:
100=2(L+W)
solving for L we get:
L=50-W
but W=25m
hence
L=50-25=25 m
thus the maximum area will be:
A=L*W=25*25=625m^2
Answer:
y =.6x+2
Step-by-step explanation:
Given:
Consider the below figure attached with this question.
m(arc(SW)) = (12x-5)°, m(arc(TV))= (2x+7)°,and measure of angle TUV = (6x-19)°.
To find:
The m(arc SW).
Solution:
Intersecting secant theorem: If two secants intersect outside the circle, then the angle on the intersection is half of the difference of the larger subtended arc and smaller subtended arc.
Using Intersecting secant theorem, we get




Multiply both sides by 2.




Divide both sides by 2.

Now, the measure of arc SW is:




Therefore, the measure of arc SW is 151 degrees.
Answer: <span>-2x-10=-2(x+5)</span>
<span>
-2x-10
Taking out common factor -2
= -2( x + 5 )</span>