If there are 4 girls to every 9 students, then there are 5 boys to every girl, 9-4=5. So, there are more boys in the class.
Answer:
The answer is below
Step-by-step explanation:
When computing quartile and decile, the data must be arranged in ascending order.
Given the data points:
13 13 13 20 26 26 29 31 34 34 35 35 36 37 38 41 41 41 42 43 46 47 48 49 53 55 56 62 67 82
The numbers are arranged in ascending order. The total number of terms is 30.
a)
![First \ quartile(Q_1)=\frac{1}{4}(n+1)^{th}\ term\\\\where\ n=number\ of\ terms. Hence:\\\\Q_1=\frac{1}{4}(30+1)=7.75^{th}\ term=average\ of\ 7th\ and\ 8th\ term=\frac{29+31}{2} =30\\\\Q_1=30\\\\Third \ quartile(Q_3)=\frac{3}{4}(n+1)^{th}\ term\\\\Q_3=\frac{3}{4}(30+1)=23.25^{th}\ term=average\ of\ 23rd\ and\ 24th\ term=\frac{48+49}{2} =48.5\\\\Q_3=48.5](https://tex.z-dn.net/?f=First%20%5C%20quartile%28Q_1%29%3D%5Cfrac%7B1%7D%7B4%7D%28n%2B1%29%5E%7Bth%7D%5C%20%20term%5C%5C%5C%5Cwhere%5C%20n%3Dnumber%5C%20of%5C%20terms.%20Hence%3A%5C%5C%5C%5CQ_1%3D%5Cfrac%7B1%7D%7B4%7D%2830%2B1%29%3D7.75%5E%7Bth%7D%5C%20term%3Daverage%5C%20of%5C%207th%5C%20and%5C%208th%5C%20term%3D%5Cfrac%7B29%2B31%7D%7B2%7D%20%3D30%5C%5C%5C%5CQ_1%3D30%5C%5C%5C%5CThird%20%5C%20quartile%28Q_3%29%3D%5Cfrac%7B3%7D%7B4%7D%28n%2B1%29%5E%7Bth%7D%5C%20%20term%5C%5C%5C%5CQ_3%3D%5Cfrac%7B3%7D%7B4%7D%2830%2B1%29%3D23.25%5E%7Bth%7D%5C%20term%3Daverage%5C%20of%5C%2023rd%5C%20and%5C%2024th%5C%20term%3D%5Cfrac%7B48%2B49%7D%7B2%7D%20%3D48.5%5C%5C%5C%5CQ_3%3D48.5)
b)
![Second \ decile(D_2)=\frac{2}{10}(n+1)^{th}\ term\\\\where\ n=number\ of\ terms. Hence:\\\\D_2=\frac{2}{10}(30+1)=6.2^{th}\ term=average\ of\ 6th\ and\ 7th\ term=\frac{26+29}{2} =27.5\\\\D_2=27.5\\\\\\Eight \ decile(D_8)=\frac{8}{10}(n+1)^{th}\ term=\frac{8}{10}(30+1)=24.8^{th}\ term\\=average\ of\ 24th\ and\ 25th\ term=\frac{49+53}{2} =51\\\\D_8=51](https://tex.z-dn.net/?f=Second%20%5C%20decile%28D_2%29%3D%5Cfrac%7B2%7D%7B10%7D%28n%2B1%29%5E%7Bth%7D%5C%20%20term%5C%5C%5C%5Cwhere%5C%20n%3Dnumber%5C%20of%5C%20terms.%20Hence%3A%5C%5C%5C%5CD_2%3D%5Cfrac%7B2%7D%7B10%7D%2830%2B1%29%3D6.2%5E%7Bth%7D%5C%20term%3Daverage%5C%20of%5C%206th%5C%20and%5C%207th%5C%20term%3D%5Cfrac%7B26%2B29%7D%7B2%7D%20%3D27.5%5C%5C%5C%5CD_2%3D27.5%5C%5C%5C%5C%5C%5CEight%20%5C%20decile%28D_8%29%3D%5Cfrac%7B8%7D%7B10%7D%28n%2B1%29%5E%7Bth%7D%5C%20%20term%3D%5Cfrac%7B8%7D%7B10%7D%2830%2B1%29%3D24.8%5E%7Bth%7D%5C%20term%5C%5C%3Daverage%5C%20of%5C%2024th%5C%20and%5C%2025th%5C%20term%3D%5Cfrac%7B49%2B53%7D%7B2%7D%20%3D51%5C%5C%5C%5CD_8%3D51)
Answer:
5x - 63 = 6
Step-by-step explanation:
Okay, first step, let's get all fractions having a common denominator, to do this, multiply 2/3 by 3 to get 6/9. Now, we have 5/9x-7=6/9. To make these into whole numbers, we can multiply the whole equation by the denominator (9). 5/9x multiplied by 9 is 5. 7 multiplied by 9 is 63. 6/9 multiplied by 9 is 6. Now we have 5x-63=6. If I were to simplify the equation, it would require decimals, so I'll leave it at this, but the equation simplified is x=13.8.
Rewrite in standard form to find the center (h,k) and redius r.
center: (2,-1)
Radius:4
have a great day!!!
I think it is option 1 sorry if wrong